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Neporo4naja [7]
3 years ago
8

Leah wants to find 450 + 416 using place value. Write the smaller problems she could use to find the sum. then find the sum.

Mathematics
2 answers:
Westkost [7]3 years ago
6 0
400+400 = 800
50+10 = 60
0+6 = 6
866
Gennadij [26K]3 years ago
5 0

Answer:

866

Step-by-step explanation:

She could add the hundreds first: 400+400=800

Then the tens: 50+10=60

Then the ones: 0+6=6

And add them all up: 800+60+6=866

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trapecia [35]

Answer:

45-n

Step-by-step explanation:

i think this is what you mean

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Show your work with long division please
Naya [18.7K]

Answer:

<h3>   __</h3><h3>0.63</h3>

Step-by-step explanation:

7/11 = no, add 0

70/11 = 6, so 0.6, remainder is 4, add 0

40/11 = 3, so 0.03, remainder is 7, add 0

70/11 = 6... and it goes on

<h3>The answer is 0.63 bar notation on both 6 and 3</h3>
4 0
3 years ago
Nelson mows lawns. He uses the equation 15x – 95 = y to find the profit, y, in dollars. He paid $95 for supplies and earns $15 f
Dovator [93]
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6 0
3 years ago
Read 2 more answers
Which expression is equivalent to...
torisob [31]

Answer:

x^{\frac{2}{7} } y^{-\frac{3}{5} } \\  i.e answer A.

Step-by-step explanation:

This question involves knowing the following power/exponent rule:

\sqrt[n]{x^m} = x^\frac{m}{n} \\\\so \sqrt[7]{x^2} = x^\frac{2}{7} \\\\and  \\\\ \sqrt[5]{y^3} = y^\frac{3}{5} \\

Next, when a power is on the bottom of a fraction, if we want to move it to the top, this makes the power become negative.

so the y-term, when moved to the top of the fraction, becomes:

y^{-\frac{3}{5} } \\

So the answer is: x^{\frac{2}{7} } y^{-\frac{3}{5} } \\

7 0
3 years ago
Angle 1 and angle 2 are vertical angles. If m angle 1 = (8x+12)° and m angle 2 = (3x+37)° find the measure for each angle.
laila [671]
Vertically opposite angles are always equal.

Given angles are (8x+12)° and (3x+37)°

=> (8x+12)° = (3x + 37)°

=> 8x - 3x = 37-12

=> 5x = 25

=> x = 25/5 = 5°

Angle 1 = (8x+12)° = (8(5)+12) = 40+12 = 52°

Angle 2 = (3x + 37)° = (3(5)+37)° = 15+37 = 52°
8 0
2 years ago
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