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nasty-shy [4]
3 years ago
10

What is the percent of change between 57000 people and 97000 people, and how do I solve it? ​

Mathematics
1 answer:
Brums [2.3K]3 years ago
8 0

Answer:

58.76

Step-by-step explanation:

So, as you can tell 97,000 is the 100 percent of the people, in this case we don't know what 57,000 is. Just divide equation 1 by equation 2. Considering both have the same unit. I'm so sorry, if this doesn't explain the best way.

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Write as a fraction.
lesantik [10]

Answer:

the answer is 5/8

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
Find the Area of the figure below,
murzikaleks [220]

Answer:

169.1 unit^2 to the nearest tenth.

Step-by-step explanation:

Area of the parallelogram = base * height

= 24 * 6 unit^2.

Area of the semicircle = 1/2 pi r^2.

Here r = 1/2 * 8 = 4.

So the area is 1/2 * pi * 4^2

= 8pi unit^2.

The area of the whole figure = 24*6 + 8pi

= 169.13 unit^2.

3 0
3 years ago
Step 1: Choose ONE of the following triangles and complete the table below:
Archy [21]

The question is incomplete below you will find the missing part.

Step 1 : Choose ONE of the following triangles complete the table below:

1. Obtuse Scalene Triangle Translation to prove SSS Congruence

or

2. Isosceles Right Triangle Reflection to prove ASA Congruence

or

3. Equilateral Equiangular Triangle Rotation to prove SAS Congruence

Original Coordinate Point

Transformation Rule

Image Coordinate Points

A (1, 4)      (x,y) -> (x+ ,y -)      A’ ( , )

B ( 7,4)     (x,y) -> (x+ ,y - )     B’ ( , )

C (8,9)      (x,y) -> (x+ ,y -)     C’ ( , )

The appropriate table is also shown below.

The triangles ABC and A'B'C' are congruent by SSS through Obtuse Scalene Triangle Translation  because the corresponding sides are congruent

Two triangles are congruent if their size and shape are the same.

Now we have to transform the triangle,

The coordinates of the triangle ΔABC are given as:

A = (1, 4)

B = (7,4)

C = (8,9)

so the lengths of the sides of the triangle are given by

AB= √(7-1)²+(4-4)²= √6²= 6

BC= √(8-7)²+(9-4)²= √1²+5²= √1+25= √26

CA= √(8-1)²+(9-4)²= √7²+5²= √49+25= √74

In order to prove the SSS congruence, we have to transform the triangles under the following translation rule:

(x,y) -> (x -3, y +6)

in the above translation,

The triangle will be translated 3 units left

And then translated 6 units up.

So, we have the new coordination of the points of the translated triangle ΔA'B'C'

A' = (1-3, 4+6)

A' = (-2, 10)

B' = (7-3, 4+6)

B' = (4, 10)

C' = (8-3, 9+6)

C' = (5, 15)

Now

so the lengths of the sides of the triangle are given by

A'B'= √(4-(-2))²+(10-10)²= √6²= 6

B'C'= √(5-4)²+(15-10)²= √1²+5²= √1+25= √26

C'A'= √(-2-5)²+(10-15)²= √(-7)²+(-5)²= √49+25= √74

By comparing two triangles ΔABC and ΔA'B'C'

AB ≅ A'B'

BC ≅ B'C'

CA ≅ C'A'

Hence ΔABC ≅ A'B'C' (By S-S-S rule)

By the above transformation, the triangles ABC and A'B'C' are congruent by SSS because the corresponding sides are congruent as all the points are gone through the same transformation.

Learn more about the transformation

here: brainly.com/question/4289712

#SPJ10

6 0
2 years ago
The rectangular walkway will be 3 feet wide and 18 feet long. each 2-foot by 3-foot stone covers an area of 6 square feet. how m
anygoal [31]
3x18=54sq ft
2x3=6sq ft
54/6=9 stones needed
7 0
4 years ago
Find the range of p in equation p(x+1) (x-3)=x-4p-2 has no real roots. ​
Tanya [424]

Answer:

\displaystyle p > \frac{1}{4}.

Step-by-step explanation:

Expand the left-hand side of this equation:

p\, (x + 1)\, (x - 3) = p\, \left(x^2 - 2\, x - 3\right) = p\, x^2 - 2\, p\, x - 3\, p.

Collect the terms, so that this quadratic equation is in the form a\, x^2 + b\, x+ c = 0:

p\, x^2 - 2\, p\, x - 3\, p = x - 4\, p - 2.

p\, x^2 - (2\, p + 1)\, x + (p + 2) = 0.

In this equation:

  • a = p.
  • b = -(2\, p + 1).
  • c = p + 2.

Calculate the quadratic discriminant of this quadratic equation:

\begin{aligned}b^2 - 4\, a\, c &= (-(2\, p + 1))^2 - 4\, p\, (p + 2) \\ &= 4\, p^2 + 4\, p + 1 - 4\, p^2- 8\, p = -4\, p + 1\end{aligned}.

A quadratic equation has no real root if its quadratic discriminant is less then zero. As a result, this quadratic equation will have no real root when -4\, p + 1 < 0. Solve for the range of p:

\displaystyle p > \frac{1}{4}.

4 0
4 years ago
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