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2 years ago

Please help!!!!!!!11

Mathematics

2 answers:

Gelneren [198K]2 years ago

5 0

A=6
b= 5

these are the answers hope they are correct

jeyben [28]2 years ago

3 0

Answer:

a = 6 , b = 5

Step-by-step explanation:

using the rule of radicals

$\sqrt{a}$ × $\sqrt{b}$ = $\sqrt{ab}$

then

$\sqrt{180}$

= $\sqrt{36(5)}$

= $\sqrt{36}$ × $\sqrt{5}$

= 6 $\sqrt{5}$

with a = 6 and b = 5

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|x| = 3 what is the answer with work

yarga [219]

When you have an absolute value equation like this, you drop the absolute value signs and change the sign of the value opposite of x.

For instance,

|x| = 3

Let's drop the || signs.

x = 3

This is one solution. Let's change the sign of 3 now.

x = -3

In conclusion,

x = 3, -3

3 0

3 years ago

Una poblacion es atacada por una epidemia de gripe sea N(t)= numero de personas enfermas al tiempo t. En dias la epidemia inicio

Lisa [10]

Answer:

Habrán 10175 enfermos a los 15 dias.

Step-by-step explanation:

La tasa de cambio de la población enferma por la epidemia de gripe es:

$N'(t)=120t-3t^2$

Donde t es el tiempo en dias, y se sabe que la epidemia inició en N(0)=50.

Para encontrar la función original que describe el comportamiento de la epidemia, debemos integrar la función:

$N(t)=\int N'(t)dt$

$N(t)=\int (120t-3t^2)dt$

Integrando:

$\displaystyle N(t)=120\frac{t^2}{2}-3\frac{t^3}{3}+C$

Simplificando:

$\displaystyle N(t)=60t^2-t^3+C$

Para determinar el valor de C, usamos la condición inicial N(0)=50:

$\displaystyle 50=60(0)^2-(0)^3+C$

Se tiene que C=50, y la función queda determinada como:

$\displaystyle N(t)=60t^2-t^3+50$

b) El número de enfermos a los t=15 dias se determina substituyendo el valor en la función original:

$\displaystyle N(15)=60(15)^2-(15)^3+50$

Calculando:

$N(15)=13500-3375+50=10175$

Habrán 10175 enfermos a los 15 dias.

8 0

3 years ago

An object is thrown straight up from the top of a 100-foot platform at a velocity of 48 feet per second. The height h(t) of the

julsineya [31]

Answer:

The maximum height is 136 ft

The time it takes to achieve this height is 1.5 s.

Explanation:

1. Function for the height (given):

$h(t)=-16t^2+48t+100$

2. Type of function

That is a quadatic function, whose graph is a parabola that opens downward.

The maximum of the function, i.e. the maximum height, is the vertex of the parabola.

The vertex of a parabola with the genral equation $y=ax^2+bx+c$ is at the x-coordinate

$x=-b/(2a)$

3. Time to achieve the maximum height

Substitute b with 48 and a with - 16:

$t=-48/(2(-16))=48/32=3/2=1.5$

Then, time when the object achieves the maximum height it 1.5s

4. Maximum height:

Replace t with 1.5 in the equation, to find the maximum height, h(1.5)

$h(1.5)=-16(1.5)^2+48(1.5)+100=136$

Then, the maximum height is 136 ft

3 0

3 years ago

Using GEMDAS, what is the simplified form of this expression? 63 x 4 = 2x2=3 - 17

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2 years ago

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SCORPION-xisa [38]

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6 0

3 years ago

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