Answer:
16 m × 11 m
Step-by-step explanation:
The dimension of the gym is 20 m x 15 m. An outbound of 2m width is to be cut out from the gym to form the basketball court.
The original length of gym = 20 m and original width of gym = 15 m
2 m would be cut at both sides of the gym length for the outbound. Also 2 m would be cut at both sides of the gym width for the outbound. Therefore:
Length of basketball court = 20 m - (2 * 2m) = 20 m - 4 m = 16 m
Width of basketball court = 15 m - (2 * 2m) = 15 m - 4 m = 11 m
Therefore the dimensions of the basketball court is:
16 m × 11 m
Answer:
a=
Step-by-step explanation:
vf=vi + at
vf-vi= at
divide both sides by t
=
a=
Answer:
A
Step-by-step explanation:
Answer:
x= 13 degrees
Step-by-step explanation:
This is a 90 degree angle. We can create an equation to find x
68+x+9= 90
77+x= 90
-77 -77
x= 13 degrees
Hope this helps!
Answer:
x intercept - = 11/2 (5.50000 as a decimal)
y intercept - = 11/1 (11.00000 as a decimal)
Step-by-step explanation:
