Answer:
vertical stretch
Step-by-step explanation:
Answer:
The last one.
Step-by-step explanation:
The standard form equation of an ellipse with foci on the y-axis is ...
y²/a² +x²/b² = 1
where "a" and "b" are the lengths of the semi-major and semi-minor axes, respectively. If "c" is the distance from the center to the focus, then this relation also holds:
b² +c² = a²
For this ellipse ...
b² + 8² = 17²
289 -64 = b² = 225 . . . . . subtract 8²
b = 15 . . . . . . . . . . . . . . . . . take the square root
The equation of the ellipse is then ...
y²/17² +x²/15² = 1
8%
4 ÷ 50 is 0.08 x 100 is 8%
Factor 8 out of 16x^2 - 24x +8
8 is the GFC
Factor the following:
16 x^2 - 24 x + 8
Factor 8 out of 16 x^2 - 24 x + 8:
8 (2 x^2 - 3 x + 1)
Factor the quadratic 2 x^2 - 3 x + 1.
The coefficient of x^2 is 2 and the constant term is 1.
The product of 2 and 1 is 2.
The factors of 2 which sum to -3 are -1 and -2.
So 2 x^2 - 3 x + 1 = 2 x^2 - 2 x - x + 1 = -(2 x - 1) + x (2 x - 1):
8 x (2 x - 1) - (2 x - 1)
Factor 2 x - 1 from x (2 x - 1) - (2 x - 1):
<span>Answer: 8 (2 x - 1) (x - 1)</span>
Slope: Take two points from the graph, and do y-y, over x-x.
for ex. (1,2) and (2,4) do 4-2 over 2-1. your slope is 2/1= 2
y-intercept: find the one point on the graph that is exactly on the y-axis.
for ex. (4,0)= your y-intercept is 4
