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3 years ago

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7 2/3 16 3/5 + 8 1/2 ______

1 answer:

____ [38]3 years ago

5 0

Answer in photo. hope this helps

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Which product is the better deal<br> A. Washing Powder<br> B. Super Clean<br> (easy)

Vesnalui [34]

Answer:

Washing Powder

Step-by-step explanation:

Cost less and cleans better.

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3 years ago

Read 2 more answers

Given: KLMN is a trapezoid, m∠N= m∠KML, FD=8, LM KN = 3/5 F∈ KL , D∈ MN , ME ⊥ KN KF=FL, MD=DN, ME=3 root5 Find: KM

Alla [95]

Answer:

The length of KM is $\sqrt{109}$ units.

Step-by-step explanation:

Given information: KLMN is a trapezoid, ∠N= ∠KML, FD=8, $\frac{LM}{KN}=\frac{3}{5}$ , F∈ KL, D∈ MN , ME ⊥ KN KF=FL, MD=DN, $ME=3\sqrt{5}$ .

From the given information it is noticed that the point F and D are midpoints of KL and MN respectively. The height of the trapezoid is $3\sqrt{5}$ .

Midsegment is a line segment which connects the midpoints of not parallel sides. The length of midsegment of average of parallel lines.

Since $\frac{LM}{KN}=\frac{3}{5}$ , therefore LM is 3x and KN is 5x.

$\frac{3x+5x}{2}=8$

$\frac{8x}{2}=8$

$x=2$

Therefore the length of LM is 6 and length of KN is 10.

Draw perpendicular on KN form L and M.

$KN=KA+AE+EN$

$10=6+2(EN)$ (KA=EN, isosceles trapezoid)

$EN=2$

$KE=KN-EN=10-2=8$

Therefore the length of KE is 8.

Use pythagoras theorem is triangle EKM.

$Hypotenuse^2=base^2+perpendicular^2$

$(KM)^2=(KE)^2+(ME)^2$

$(KM)^2=(8)^2+(3\sqrt{5})^2$

$KM^2=64+9(5)$

$KM=\sqrt{109}$

Therefore the length of KM is $\sqrt{109}$ units.

5 0

3 years ago

Plz answer my question -(4b-6b-7b)

GalinKa [24]

Step-by-step explanation:

-(4b-6b-7b)

= -4b+6b+7b

=9b

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3 years ago

The angle of the elevation of the sun is 34 degrees. Find the length, l, of a shadow cast by a tree that is 53 feet tall. Round

gulaghasi [49]

$\tan{34^o}= \frac{53}{x} 
\\
\\x= \frac{53}{\tan{34^o}} 
\\
\\x \approx 78.58$

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4 years ago

Please help me! asap!!

svet-max [94.6K]

Answer:

C

Step-by-step explanation:

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3 years ago