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4 years ago

Please answer the top half ASAP I need it in 2h please

Mathematics

1 answer:

NeTakaya4 years ago

4 0

Answer:

4/7
6/11
12/17
19/30
10/17
7/15
11/28
8/21
7/3
23/49
3/7
1/2
4/7
5/22
3/7
3/4
1/3
1/10
3/8
1/2
3/8
4/7
65/168
8/21
40/63
4/3
1/2
9/7
9/5
21/44

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3 years ago

A news station would like to conduct an exit poll to determine the likelihood that a highly debated amendment will receive enoug

vladimir1956 [14]

Answer:

The expression is $n = (\frac{1.645*0.5}{0.03})^2$

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a p-value of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

What expression would give the smallest sample size that will result in a margin of error of no more than 3 percentage points?

We have to find n for which M = 0.03.

We have no prior estimate for the proportion, so we use $\pi = 0.5$ . So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 1.645\sqrt{\frac{0.5*0.5}{n}}$

$0.03\sqrt{n} = 1.645*0.5$

$\sqrt{n} = \frac{1.645*0.5}{0.03}$

$(\sqrt{n})^2 = (\frac{1.645*0.5}{0.03})^2$

$n = (\frac{1.645*0.5}{0.03})^2$

The expression is $n = (\frac{1.645*0.5}{0.03})^2$

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3 years ago

Solve for x. (TYPE ONLY THE NUMBER FOR YOUR ANSWER).

scoray [572]

9514 1404 393

Answer:

x = 7

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The sum of angle measures in a quadrilateral is 360°.

(8x-5)° +107° +83° +119° = 360°

8x = 56 . . . . . . . divide by °, subtract 304

x = 7 . . . . . . . . . . divide by 8

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3 years ago