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andrew11 [14]
3 years ago
13

What is the ratio for erasers to pencils?

Mathematics
1 answer:
poizon [28]3 years ago
7 0
4:3 it four to three
You might be interested in
What is 2/3 ÷ 4/5 = ?
11Alexandr11 [23.1K]

Answer:

5/6

Step-by-step explanation:

  • 2/3 ÷ 4/5 =                ⇒  <em>changing division to multiplication by reciprocal of the second fraction</em>
  • 2/3 × 5/4 =                ⇒  <em>simplify and multiply numerators and denominators</em>
  • 5/6                           ⇒  <em>here is the answer</em>
3 0
4 years ago
What is the axis of symmetry gor Graph A​
Lady_Fox [76]

Answer:

X=-2

Step-by-step explanation:

The axis of symmetry for any parabola is the x value of the vertex. Dividing the parabola along the vertex will always yield two symmetric halves.

7 0
4 years ago
Solve for x number 11
Julli [10]

Answer:b

Step-by-step explanation:

5 0
3 years ago
Which graph represents the function of f(x) = 9x 2 -36/3x+6 Please help
UkoKoshka [18]
The function is:

             (9x^2 - 36)
f(x) = ---------------------
                3x + 6

You can simplify that function to a linear function for all x for which 3x + 6 ≠ 0

=> x ≠ - 2.

So, for x ≠ - 2, you can do:


             (9x^2 - 36)
f(x) = --------------------- =
               3x + 6

              9(x^2 - 4)
f(x) = ---------------------
                3(x + 2)

             3(x + 2)(x - 2)
f(x) = --------------------- = 3(x - 2) = 3x - 6
                 (x + 2)

So, the graph is a right line that intercepts the y-axis at - 6 and the x-axis at x = 2, excluding x = -2 as the function is not defined for x = -2. That is the second graph of the second picture.


6 0
3 years ago
The table below gives data from a linear function. find a formula for the function.
baherus [9]
Given the following table that gives data from a linear function:

\begin {tabular}&#10;{|c|c|c|c|}&#10;Temperature, $y = f(x)$ (^\circ C)&0&5&20 \\ [1ex]&#10;Temperature, $x$ (^\circ F)&32&41&68 \\ &#10;\end {tabular}

The formular for the function can be obtained by choosing two points from the table and using the formular for the equation of a straight line.

Recall that the equation of a straight line is given by
\frac{y-y_1}{x-x_1} = \frac{y_2-y_1}{x_2-x_1}

Using the points (32, 0) and (41, 5), we have:
\frac{y-0}{x-32} = \frac{5-0}{41-32}= \frac{5}{9}  \\  \\ \Rightarrow y=\frac{5}{9}(x-32)
4 0
3 years ago
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