Solution
Given the quadratic equation
we need to find the zeros of the equation
To do that, we use the completing the square method
Step 1. Add 38 to both sides
Step 2: add the square of half of the coefficient of x to both sides
That is;
Step 3: Simplify the above expression;
![\begin{gathered} \Rightarrow x-1=\pm\sqrt[]{39} \\ \\ \Rightarrow x=1\pm\sqrt[]{39} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5CRightarrow%20x-1%3D%5Cpm%5Csqrt%5B%5D%7B39%7D%20%5C%5C%20%20%5C%5C%20%5CRightarrow%20x%3D1%5Cpm%5Csqrt%5B%5D%7B39%7D%20%5Cend%7Bgathered%7D)
Answer:
Step-by-step explanation:
m∠EBC = 45°
3x + 9y = 45
Divide the entire equation by 3
x + 3y = 15 --------------------(I)
m∠EAB = 45
5x + 5y = 45
Divide the entire equation by 5
x +y = 9 -------------(II)
Multiply equation (II) by (-1)
(I) x + 3y = 15
(II)*(-1) <u> - x - y = -9</u> {Now add}
2y = 6
y = 6/2
y = 3
Plugin y = 3 in equation (I)
x + 3*3 = 15
x + 9 = 15
x = 15 - 9
x = 6
Answer:
18x^2-12xy+6y^2
Step-by-step explanation:
use FOIL
First
Outter
Inner
Last
From the second equation we can find that d=43-(9/10)*n
we can put this equation into the first one,
So we have equation 60(43-(9/10)*n)+65n=2800
Solving that we get n=20
60d+65*20=2800
d=25
So the answer is d=25 and n=20
