In order for the rectangle to have an area of 6 cm^2, Tomas could have drawn it with one of two side length possibilities. He could either have drawn a rectangle with a length of 6 and a width of 1, or a rectangle with a length of 3 and a width of 2.
To find perimeter, you just add up all side lengths together, so let's compare the two options to find out which one has a greater perimeter.
Let's try the first option first.
That would be 6 + 6 + 1 + 1, which is 14.
Let's try the other one.
3 + 3 + 2 + 2 = 10
The first option (width 1, length 6) would yield the greatest perimeter.
Hope that helped! =)
I assume the question asks to expand the expression to individual terms.
There are different ways to approach this, all based on FOIL or similar methods.
I prefer to split it into two parts, as follows:
(x+y+2)(y+1)
=x(y+1)+(y+2)(y+1)
=xy+x+y^2+3y+2
Answer:
The length of the pencils is 4.1 inches and for the crayons 1.5 inches
Step-by-step explanation:
We can solve by means of a 2x2 system of equations, we have to:
let "x" be the length of the pencils
let "y" be the length of the crayons
4 * x + 3 * y = 20.9
5 * x + 4 * y = 26.5 => x = (26.5 - 4 * y) / 5
Replacing:
4 * (26.5 - 4 * y) / 5 + 3 * y = 20.9
21.2 - 3.2 * y + 3 * y = 20.9
-0.2 * y = 20.9 - 21.2
y = -0.3 / -0.2
y = 1.5
now for x:
x = (26.5 - 4 * 1.5) / 5
x = 4.1
This means that the length of the pencils is 4.1 inches and for the crayons 1.5 inches
Answer:
C. 6
Step-by-step explanation:
6*1=6
6*3=18
6*4=24
6*7=42
Hope this helps!
If not, I am sorry.
Step-by-step explanation:
id assume its -5 as the rate of change seems to be zero
