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quester [9]
3 years ago
15

Solve for x number 11

Mathematics
1 answer:
Julli [10]3 years ago
5 0

Answer:b

Step-by-step explanation:

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Which expression represents the area of the parallelogram below?
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A is the answer because to find a area you need to multiply each side
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In the supply-and-demand schedule shown above, the equilibrium price for portable music players is _____.
ad-work [718]
$150 because the supply number is equivalent to the demand number
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Read 2 more answers
Three fourths a number plus 8 is 20 less than the number
VARVARA [1.3K]

Answer:

Equation:  \frac{3}{4}n+8=n-20

Solve for n:  n = 112

Step-by-step explanation:

To first set up the equation, you need to look at the verbal description and translate into numbers and operations:

'three fourths a number' =  \frac{3}{4} n

'plus 8' = + 8

'is' =

'20 less' = - 20

'the number' = n

Put the expressions together:

'three fourths a number plus 8':  \frac{3}{4}n+8

'20 less than the number': n - 20

Set them equal to each other and solve: \frac{3}{4}n+8=n-20

Add 20 to both sides: \frac{3}{4}n+8+20=n-20+20

Subtract \frac{3}{4}n from both sides: \frac{3}{4}n-\frac{3}{4}n+28=n-\frac{3}{4}n

Multiply both sides by \frac{4}{1}: \frac{4}{1}28=\frac{1}{4}n\frac{4}{1}

Solve for n:  n = 112

7 0
3 years ago
Suppose p" must approximate p with relative error at most 10-3 . Find the largest interval in which p* must lie for each value o
goblinko [34]

Answer:

[p-|p|*10^{-3} \, , \, p+|p|* 10^-3]

Step-by-step explanation

The relative error is the absolute error divided by the absolute value of p. for an approximation p*, the relative error is

r = |p*-p|/|p|

we want r to be at most 10⁻³, thus

|p*-p|/|p| ≤ 10⁻³

|p*-p| ≤ |p|* 10⁻³

therefore, p*-p should lie in the interval [ - |p| * 10⁻³ , |p| * 10⁻³ ], and as a consecuence, p* should be in the interval  [p - |p| * 10⁻³ , p + |p| * 10⁻³ ]

8 0
3 years ago
Graph the system &amp; write its solution <br> 2x+y=-4<br> Y=-1/2x-1
xz_007 [3.2K]

Answer:

The solution of system of equation is (-2,0)

Step-by-step explanation:

Given system of equation are

Equation 1 :      2x+y=(-4)

Equation 2 :      y+\frac{1}{2}x=(-1)

To plot the equation of line, we need at least two points

For Equation 1 : 2x+y=(-4)

Let x=0

2x+y=(-4)

2(0)+y=(-4)

y=(-4)

Let x=1

2x+y=(-4)

2(1)+y=(-4)

y=(-6)

Therefore,

The required points for equation is (0,-4) and (1,-6)

For Equation 2 : y+\frac{1}{2}x=(-1)

Let x=0

y+\frac{1}{2}x=(-1)

y+\frac{1}{2}(0)=(-1)

y=(-1)

Let x=2

y+\frac{1}{2}x=(-1)

y+\frac{1}{2}(2)=(-1)

y=(-2)

The required points for equation is (0,-1) and (2,-2)

Now, plot the graph using this points

From the graph,

The red line is equation 1 and blue line is equation 2

Since. The point of intersection is solution of system of equations

The solution of system of equation is (-2,0)

6 0
3 years ago
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