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Helen [10]
3 years ago
6

WORTH 15 POINTS:

Mathematics
1 answer:
Westkost [7]3 years ago
5 0

Answer:

84

Step-by-step explanation:

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Justin is going to invest $31,000 and leave it in an account for 7 years.
galina1969 [7]

Answer:

5.4 percent

Step-by-step explanation:

4 0
3 years ago
What is an equation of the line that passing through the points (-2, -5) and (4, 7) ?
monitta

Answer:

y=2x-1

Step-by-step explanation:

Use the slope-intercept formula: y=mx+b where m is slope and b the y-intercept.

(-2,-5)(4,7)

Use the slope formula for when you have two points:

\frac{y(2)-y(1)}{x(2)-x(1)}=\frac{rise}{run}

Rise over run is the change in the y-axis over the change in the x-axis. Insert values:

\frac{7-(-5)}{4-(-2)}

Simplify parentheses (negative+negative=positive)

\frac{7+5}{4+2}

Simplify

\frac{12}{6}=2

2 is the slope:

y=2x+b

Now use one of the points to find the y-intercept by substituting the x and y values into the equation. Solve for b:

(4,7)

y=2x+b\\7=2(4)+b

7=8+b\\7-8=8-8+b\\7-8=b\\-1=b\\b=-1

The y-intercept is -1. Insert into the equation. Change the + symbol to -:

y=2x-1

Done.

6 0
3 years ago
1. Use separation of variables to find the solution to the differential equation subject to the given initial condition.
andrew11 [14]

Answer:

Step-by-step explanation:

Given the differential equation dy/dx = 5y/x subject to the condition y = 4 and x = 1. Using the variable separable method of solving differential equation, we will have;

dy/dx = 5y/x

Separate the variables

dy/5y = dx/x

Integrate both sides of the expression

\frac{1}{5}\int\limits \frac{1}{y}  \, dy = \int\limits \frac{dx}{x} \\ \\\frac{1}{5}lny = lnx + C\\\\lny = 5lnx+5C\\

using the initial condition y = 4 while x = 1

ln4 = 5ln1 + 5C

ln4 = 0+5C

C = ln4/5

Substituting the value of C back into the expression;

lny = 5 lnx+5(ln4/5)\\lny = 5lnx+ln4\\lny = lnx^5+ln4\\lny = ln(4x^5)\\y = 4x^5

<em>Hence the solution to the differential equation is y = 4x⁵</em>

<em></em>

b) Given 4(du/dt) = u²

du/dt = u²/4

du/ u² = dt/4

u⁻²du = 1/4 dt

integrate both sides of the equation

\int\limit {u^{-2}} \, du  = \int\limits\frac{1}{4}  \, dt\\\\\frac{u^{-1}}{-1} = \frac{t}{4} + C\\\\\frac{-1}{u} =  \frac{t}{4} + C

Imputing the initial condition u(0) = 7 i.e when t = 0, u = 7

\frac{-1}{7} =  \frac{0}{4} + C\\\\\frac{-1}{7} =  C\\

\frac{-1}{u} =  \frac{t}{4} - \frac{1}{7}

<em>Hence the solution to the DE is </em>\frac{-1}{u} =  \frac{t}{4} - \frac{1}{7}

6 0
3 years ago
Help me with this yes im lazy 2 pages thats it.
valentinak56 [21]

Answer:

2.)\frac{1}{4}/3=\frac{1}{4}*\frac{1}{3}=\frac{1}{12} s yes she is correct

3.)\frac{1}{5}*\frac{1}{7}

4.)C\frac{1}{5}/2= \frac{2}{5},D\frac{1}{12}/5=\frac{1}{60},E

6.)\frac{1}{8}/3=\frac{1}{24}

Step-by-step explanation:

im not very good at word problems so i didnt do the secnd page sorry

5 0
3 years ago
It is now 10:29
Anon25 [30]

I believe this question asks if Suzette will make it on time. From 10:29 am to 10:30 am, she only has 1 minute or 60 seconds to spare.

Calculating all the times:

35 m / (3.5 m/s) = 10 s

48 m / (1.2 m/s) = 40 s

60 m / (5 m/s) = 12 s

So total time is = 62 s

<span>Hence Suzette will be late by 2 seconds.</span>

4 0
3 years ago
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