Let x is the price for one ticket in section A and y for section B.
In first week they paid <span>$108 for 6 tickets in section A and 10 tickets in section B.
So,
6x + 10y = 108
And in t</span><span>he following week, they paid $104 for 4 tickets in section A and 12 tickets in section B.
So,
4x + 12y = 104
12y = 104 -4x
y= (104 -4x) /12
now, put this value for y in first equation
6x +10(104 - 4x / 12) = 108
multiplying all terms with 12
72x +10(104 -4x) = 1296
72x + 1040 -40x = 1296
32x = 256
x = 8
So, price for one ticket in section A is $8.
</span>
Answer:
Step 1 Eliminate fractions by multiplying all terms by the least common denominator of all fractions.
Step 2 Simplify by combining like terms on each side of the inequality.
Step 3 Add or subtract quantities to obtain the unknown on one side and the numbers on the other.
Hope that helped happy holidays!
Hi!
All the given answers are <span>polynomials
</span><span>A.20x² + y
B.20x*2+y*12
C.20x*2*y
D.20x²</span>
<h2>
<em>Answer:</em></h2><h2>
<em>9</em><em>x</em><em>+</em><em>8</em><em>c</em><em>+</em><em>4</em></h2>
<em>Solution</em><em>,</em>
<em>(</em><em>9</em><em>x</em><em>+</em><em>9</em><em>)</em><em>+</em><em>(</em><em>8</em><em>c</em><em>-</em><em>5</em><em>)</em>
<em>=</em><em>9</em><em>x</em><em>+</em><em>9</em><em>+</em><em>8</em><em>c</em><em>-</em><em>5</em>
<em>=</em><em>9</em><em>x</em><em>+</em><em>8</em><em>c</em><em>+</em><em>9</em><em>-</em><em>5</em>
<em>=</em><em>9</em><em>x</em><em>+</em><em>8</em><em>c</em><em>+</em><em>4</em>
<em>hope </em><em>it</em><em> helps</em>
<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>
