First, a bit of housekeeping:
<span>The meaning of four consecutive even numbers is 15. Wouldn't that be "mean," not meaning? Very different concepts!
The greatest of these numbers is _______ a^1
"a^1" means "a to the first power. There are no powers in this problem statement. Perhaps you meant just "a" or "a_1" or a(1).
The least of these numbers is ______a^2.
No powers in this problem statement. Perhaps you meant a_2 or a(2)
In this problem you have four numbers. All are even, and there's a spacing of 2 units between each pair of numbers (consecutive even).
The mean, or arithmetic average, of these numbers is (a+b+c+d) / 4, where a, b, c and d represent the four consecutive even numbers. Here this mean is 15. The mean is most likely positioned between b anc c.
So here's what we have: a+b+c+d
------------- = 15
4
This is equivalent to a+b+c+d = 60.
Since the numbers a, b, c and d are consecutive even integers, let's try this:
a + (a+2) + (a+4) + (a+6) = 60. Then 4a+2+4+6=60, or 4a = 48, or a=12.
Then a=12, b=14, c=16 and d=18. Note how (12+14+16+18) / 4 = 15, which is the given mean.
We could also type, "a(1)=12, a(2)=14, a(3) = 16, and a(4) = 18.
</span>
Answer:
11
Step-by-step explanation:
If i am correct n= the days so with the days adding up day 10 juan would have 55 of the 100 candies, day 11 he would have 66. The statement said at least 64, so it would have to be 64 or the closet amount to 64 but it cannot be lower than 64. So there for 66 is the closest to the given amount, and in order for juan to get 64 he would need to take candies out for 11 days.
Answer:
Step-by-step explanation:
6*[4-(42-63)]=
6*[4-(-21)]=
6*[4+21]=
6*25=150.
6*[4-9÷3]=
6*[4-27]=
6*(-23)=-138.
6*[4-3]=
6*1=6.
Answer:
x= 3
y = 0
Step-by-step explanation:
•Add the two equations to cancel out +6x and -6x
•Find the value of y
•Substitute the value of y into equation 1 to find the value of x.
Hope I was able to help you:)
Answer:
x=4
Step-by-step explanation:
√x+12=x
x+12=x2(Square both sides)
x+12=x2
x+12−x2=x2−x2(Subtract x^2 from both sides)
−x2+x+12=0
(−x−3)(x−4)=0(Factor left side of equation)
−x−3=0 or x−4=0(Set factors equal to 0)
x=−3 or x=4
x=−3(Doesn't work in original equation)
x=√x+12
