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Diano4ka-milaya [45]
3 years ago
14

ASAP PLZ

Mathematics
2 answers:
Cloud [144]3 years ago
8 0

Answer:

3/9 because theyre both equivalent to 1/3

Elena L [17]3 years ago
3 0

Answer:

3/9

Step-by-step explanation:

2/6 is equal to 1/3, so isn't 3/9.

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MAKE YOU THE BRAINLIEST EASY QUESTION Show the formula for finding the area of a triangle. Then find the area of a right triangl
lesya692 [45]

Answer:

Formula to find the area of a triangle is 1/2(bxh). The area of the right triangle is 28.

Step-by-step explanation:

To solve this problem you would plug in the base and height into the formula and follow the order of operations (P.E.M.D.A.S). So the equation would then read 1/2(5x11.2). Once you solve inside the parenthesis, the equation then reads, 1/2(56). Then you solve what half of 56 is, which is 28.


I hoped this helped you!

6 0
3 years ago
Read 2 more answers
Write the equation in its equivalent logarithmic form.
Oksanka [162]
Logₐx=b means aᵇ=x
reverse

aᵇ=x means logₐx=b
so
2³=x means log₂x=3

I say it is A


4 0
3 years ago
Read 2 more answers
PLEASE HELP!!!!<br> I need to solve for a, b, and c
nirvana33 [79]

Answer:

  • 25000 seats in section A
  • 14100 seats in sectin B
  • 10900 seats in section C

Step-by-step explanation:

The problem statement tells you half the total number of seats are in section A, so you already know that there are 25000 A seats. The revenue from those seats is

... 25000×$25 = $625,000

so the revenue from B and C seats must total

... $1,070,500 - 625,000 = $445,500

If all 25000 of the B/C seats were C seats, the revenue would be

... 25000×$15 = $375,000

The actual revenue from those seats is $445,500 -375,000 = $70,500 more than that. We know each B seat generates $5 more revenue, so there must be ...

... $70,500/$5 = 14,100 . . . . B seats

Then the balance of the 25000 B and C seats are C seats:

... 25,000 - 14,100 = 10,900 . . . . C seats

_____

<em>Alternate Solution Method</em>

The new Brainly answer format requires the answer be supplied before the working. In order to find the answer quickly so that I can fill in that section, I used a matrix method for solving the problem. The problem equations can be written ...

  • a + b + c = 50000
  • a - b - c = 0
  • 25a + 20b + 15c = 1070500

so the augmented matrix is ...

\left[\begin{array}{cccc}1&1&1&50000\\1&-1&-1&0\\25&20&15&1070500\end{array}\right]

A graphing calculator can be used to find the solution to this, generally using a function that produces the reduced row-echelon form. The attachment shows the solution using a TI-84 calculator.

___

<em>Comment on the Working</em>

Since the number of A seats is equal to the total of B and C seats, the number of A seats must be half the total number of stadium seats. Having figured that out, the problem is reduced to one of finding the mix of B and C seats that will produce the remaining revenue.

As with many mixture problems, it is convenient to look at differences. Start with the assumption that all of the desired revenue comes from the least contributor. Here, that is C seats. Then figure the difference that using a B seat makes ($20 -15 = $5) and the difference of the actual revenue and the amount that you got by assuming all C seats: 445,500 -375,000 = 70,500. Since replacing a C seat by a B seat adds $5 to the revenue, it is easy to figure the number of such replacements required in order to raise the revenue by $70,500.

If you write the equation for B seats, you find the solution to the equation mirrors this verbal description:

... 20b + 15(25000-b) = 445,500

... 5b = 445,500 - 375000 . . . . simplify, subtract 375000

... b = 70500/5 = 14100

8 0
3 years ago
A board game has 25 cards, each printed with a number from 1 through 25. Sameer shuffled the cards, and then selected 1 card.
Yuki888 [10]

Total number of cards = 25 .
Total number of possible draws = 25
Number of possible successes = 5

(The successful draws are 1, 2, 3, 9, and 18.)

Probability of success = 5/25  =  <em>1/5 </em> =  0.2  =  20%


7 0
3 years ago
Tony misplaced
cricket20 [7]
First we multiply 7 and 0.15 to see how many he lost. We get 1.50 so now we know he lost 1.50 of his collection. we add 5.55 and 1.50 and get 7.05 we divide 7.05 by 0.15 47.
Tony had 47 stamps
8 0
3 years ago
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