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Llana [10]
2 years ago
6

If x = − 6 and y = 2 , evaluate the following expression: 2 ( y − 3 x y )

Mathematics
1 answer:
grigory [225]2 years ago
8 0

       \rule{50}{1}\large\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}

     <em>If x=-6 and y=2, evaluate 2(y-3xy)</em>

<em />

<em>      </em>\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}

  First, We need to simplify the expression by multiplying the parentheses by 2:-

\longmapsto\sf{2y-6xy}

Now , Replace y with 2 and x with -6:-

\longmapsto\sf{2(2)-6(-6)(2)}

Simplifying,

\longmapsto\sf{4-6(-12)}

Further simplifying,

\longmapsto\sf{4+72}

Adding,

\longmapsto\underline{\boxed{\sf{76}}}

<h3 /><h3>Good luck with your studies.</h3>

#TogetherWeGoFar

\rule{300}{1}

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The lengths of pregnancies in a small rural village are normally distributed with a mean of 264.1 days and a standard deviation
KiRa [710]

Answer:

The range of the 95% data (X) =  238.3 days <  X < 289.9 days

Step-by-step explanation:

Given;

mean of the normal distribution, m = 264.1 days

standard deviation, d = 12.9 days

between two standard deviation below and above the mean is 96% of all the data.

two standard deviation below the mean = m - 2d

                                                                   = 264.1 - 2(12.9)

                                                                   = 238.3 days

two standard deviation above the mean = m + 2d

                                                                    = 264.1 + 2(12.9)

                                                                     = 289.9 days

The middle of the 95% of most pregnancies would be found in the following range;

238.3 days <  X < 289.9 days

5 0
3 years ago
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Step-by-step explanation:

4 0
3 years ago
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SOVA2 [1]
<span>With 1026 being the mean score on the SAT and StDev of 209, Jessica has a score of 799/209 z-scores above the mean. Her z-score would be 3.823. The mean of the ACT and StDev are 20.8 and 4.8, respectively. A 28 ACT score would be 7.2/4.8 z-scores above the mean, for a z = 1.500. This means that Jessica has the higher z-score.</span>
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Answer:

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