Answer:
frequency of allele “A” is .39
frequency of allele “a” is .77
Explanation:
hardy weinberg equation
p^2 + 2pq + q^2 = 1 or (A+a)^2
p^2 = (AA)
2pq = (Aa)
q^2 = (aa)
AA -> 15/100 = .15
Aa -> 25/100 = .25
aa -> 60/100 = .60
if p^2 = AA = .15 then A = √.15 = 0.38729833462 = .39
if q^2 = aa = .60 then a = √.60 = 0.77459666924 = .77
wikipedia quoraAnkitGauba
Soo whats the question??????
Answer: D
Explanation: The consumption of fish especially the small fish e.g shellfish is by far the most significant source of ingestion-related mercury exposure in humans and animals.
Answer:
cosmic background radiation
Explanation:
hope this helps!!
The following phenotypic classes reflect offspring that were generated as a result of a crossover event
- miniature wings
- garnet eyes
Explanation:
When the miniature wings and garnet eyes links up with the 8 map unit that are present between them. After that the presence of two recombinant classes must complement together and make 8% of total i.e. they contribute 4% each. together the parental classes make up to 92% by contributing 46% one.
This can be understood through a phenotypic ratio calculation, which can be expected from it.
wild type: 4% x 800 = 32
miniature wings: 46% x 800 = 368
garnet eyes: 46% x 800 = 368
miniature wings, garnet eyes: 4% x 800 = 368
