All categories

3 years ago

Solving inequalities breakout

Mathematics

1 answer:

ki77a [65]3 years ago

3 0

ANSWER:
#1 = A
W≤-1

#2= I
X>-2

#3= K
X≤-6

#4= D
K≥7

You might be interested in

A cylinder has a volume of 8792 cubic units. If the height is 7 cubic u it’s which of the following is the radius

natima [27]

Answer:

20 units

Step-by-step explanation:

Volume of a cylinder = πr²h

V = πr²h

height, h = 7

V = π * r² * 7

V = 8792

8792 = 21.991148 * r²

r² = 8792 / 21.991148

r² = 399.79722

r = √399.79722

r = 19.99unit

r = 20 units

4 0

3 years ago

At wild thing zoo, you can rent a motorized cart to tour grounds for a $3 initial charge and $7 per hour. at safari zoo, you can

makvit [3.9K]

When setting up the equation you have the initial fee and the hourly fee. The hourly fee is what must be multiplied by the number of hours which is our unknown

6 0

3 years ago

A force F=-2i+j+k acts at point A(1,5,1) on a solid which is free to turn about a fixed point Q(-1,2,1). Find the torque exerted

DerKrebs [107]

The torque exerted by the force on the body is $\vec \tau = 3\,\hat{i}-2\,\hat{j} + 8\,\hat{k}$ .

Vectorially speaking, the torque exerted ( $\vec \tau$ ) by the force on the body ( $\vec F$ ) is resulted from this expression:

$\vec \tau = \vec r_{QA} \times \vec F$ (1)

Where:

$\vec r_{QA}$ - Vector distance between points A and Q.
$\vec F$ - Vector force exerted at point A.

If we know that $\vec r_{QA} = (2, 3, 0)$ and $\vec F = (-2, 1, 1)$ , then the torque is:

$\vec \tau = \left|\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\2&3&0\\-2&1&1\end{array}\right|$

$\vec \tau = (3, -2, 8)$

The torque exerted by the force on the body is $\vec \tau = 3\,\hat{i}-2\,\hat{j} + 8\,\hat{k}$ .

To learn more on torque, we kindly invite to check this verified question: brainly.com/question/3388202

8 0

2 years ago

The area of a circle (A) is given by the formula A=r^2 where r is the circle's radius. The formula to find r is______ . If (A)=5

9966 [12]

Answer: (A) and (A)

<u>Step-by-step explanation:</u>

$A=\pi \cdot r^2\\\\\dfrac{A}{\pi}=r^2\\\\\sqrt{\dfrac{A}{\pi}}=r\ \rightarrow \ \bigg(\dfrac{A}{\pi}\bigg)^{\dfrac{1}{2}}\\\\\\\\r=\sqrt{\dfrac{A}{\pi}}\\\\.\ =\sqrt{\dfrac{54\cdot 7}{22}}\\\\.\ =\sqrt{\dfrac{27\cdot 7}{11}}\\\\.\ =\sqrt{\dfrac{189}{11}}\\\\.\ =\sqrt{17.1818}\\\\.\ =4.15$