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Sliva [168]
3 years ago
8

The coordinate of centroid of a triangle whose vertices are (1,3,-2), (4,5,0), (6,3,9) is = ……………….

Mathematics
1 answer:
Dominik [7]3 years ago
8 0

Answer:

C = (\frac{11}{3},\frac{11}{3},\frac{7}{3})

Step-by-step explanation:

Given

(x_1,y_1,z_1) = (1,3,-2)

(x_2,y_2,z_2) = (4,5,0)

(x_3,y_3,z_3) = (6,3,9)

Required

Determine the coordinates of the centroid

Represent the coordinates with C.

C is calculated as follows:

C = (\frac{1}{3}(x_1+x_2+x_3),\frac{1}{3}(y_1+y_2+y_3),\frac{1}{3}(z_1+z_2+z_3}))

Substitute values of x and y in the given equation

C = (\frac{1}{3}(1+4+6),\frac{1}{3}(3+5+3),\frac{1}{3}(-2+0+9}))

C = (\frac{1}{3}(11),\frac{1}{3}(11),\frac{1}{3}(7}))

C = (\frac{11}{3},\frac{11}{3},\frac{7}{3})

<em>The above is the coordinate of the centroid</em>

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Step-by-step explanation:

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3 years ago
Phil strung two sets of lights around the window of his store. The first set of lights blinks every 30s and the second every 45s
Amiraneli [1.4K]

Answer:

Every 90 seconds, the two sets of light blink together.

Step-by-step explanation:

Given that there are two sets of lights.

First light blinks at every 30s and

Second light blinks at every 45s

To find:

How often the sets of lights blink together?

Solution:

As per given statement,

First light blinks after 30s, 60s, <u>90s</u>, 120s, 150s, <u>180s</u>, ........

Second light blinks after 45s, <u>90s</u>, 135s, <u>180s</u>, .....

If we look at the common time, shown by underlining it, the two sets of light blink at the same time after 90s, 180s, ...... and so on.

So, the two lights blink together after every 90s.

This can also be solved by finding LCM (Least Common Multiple) of the two numbers i.e. 30 and 45.

Let us have a look at the factors of 30 and 45.

30 = 2 \times <u>3</u> \times <u>5</u>

45 = 3 \times <u>3</u> \times <u>5</u>

<u />

So, LCM = 2 \times 3 \times 3 \times 5 = <em>90</em>

<em></em>

So, after every <em>90s, </em>the lights will blink together.

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Step-by-step explanation:

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3 years ago
if an amount of $5,000 is deposited into a savings account at an annual interest rate of 5%, compounded monthly, what is the val
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Answer:

$8,240

Step-by-step explanation:

We are given that,

Principle amount in the savings account, P = $5,000.

Rate of interest, r = 5% = 0.05

Time period, t = 10

Also, the interest is compounded monthly, n = 12

As, we now that the value of the investment is given by P(1+\frac{r}{n})^{nt}

Thus, we have,

Investment Value = 5000(1+\frac{0.05}{12})^{12\times 10}

i.e. Investment Value = 5000(1+\frac{0.05}{12})^{12\times 10}

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