Please help me answer these 2 questions, worth lots of points
1 answer:
You might be interested in
If the roots of the equation f(x)=0 are -4,-1, 2 and 5, then binomials (x+4), (x+1), (x-2) and (x-5) are factors of needed polynomial.
Thus, the polynomial will have form
where a is real coefficient (positive or negative). This polynomial has degree 4 as needed.
The form of the graph depends on the sign of coefficient a. Attached diagrams show two different cases of possible forms of graphs (first one for positive coefficient a, second one for negative coefficient a).
Given that <span>DG, EG, and FG are perpendicular bisectors of the sides of △ABC, this means that the point of intersection, G, is the circumcenter of the triangle and hence A</span><span>G, BG, and CG are equal.
Given that </span><span>DG = 5 cm and BD = 12 cm, then
Since AG = BG = CG, therefore, CG = 13 cm.</span>
Given that </span><span>DG = 5 cm and BD = 12 cm, then
Since AG = BG = CG, therefore, CG = 13 cm.</span>