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attashe74 [19]
3 years ago
14

A school team won 6 games this year against 4 games won last year . What is the percent increase .

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
8 0

Answer:

The increase in the number of wins (or amount of change) =6−4=2

Percentage increase

=

original amount or base

amount of change

×100

=

4

2

×100

=50%

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liraira [26]
So just your normal equation. 
We need to isolate x alone. 
First lets write out our equation 
3 +7x = 12 

Lets do this step by step. 

first subtract 3 from both sides. 
3 + 7x = 12  
-3        = -3  it cancels out on the left side and we solve on the right side. 
*************
7x = 9 

second we divide both sides by 7 
7x = 9 
÷7 = 7      we got the x alone and we just write 9/7 as our answer. 

x = 9/7 

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Either will work. 
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Averages woman's brain: 1 3/10 kg (kilograms), 2 8/10 lbs (pounds), Average human heart, 3/10 kg, 7/10 lbs, What Is the total we
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3 years ago
Reggie invests $12,000, part at 7% annual interest and part at 8.5% annual interest. how much is invested at each rate if reggie
Vika [28.1K]

Let us say that:

x = invested at 7%

y = invested at 8.5%

and that:

<span>x + y  = 12,000</span>

We can also say that:

0.07 x + 0.085 y = 900

 

Therefore:

0.07 x + 0.085 (12000 – x) = 900

0.07 x + 1020 – 0.085 x = 900

- 0.015 x = -120

x = $8000

 

so y is:

y = 12000 – 8000

y = $4,000


$8000 is invested at 7% annual interest while $4000 is invested at 8.5%

3 0
4 years ago
How much solutions does 2x = 2x + 1 have?
Leto [7]

Answer:

no solution

Step-by-step explanation:

hope this helps! :D

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5 0
3 years ago
A study of the relationship between age and various visual functions (such as acuity and depth perception) reported the followin
maks197457 [2]

Answer:

(a) \sum x_i=56.68 and \sum x_i^2=197.46

(b) The sample variance is s^2=0.530 and the sample standard deviation is s=0.728

Step-by-step explanation:

(a)

The sum of these 17 sample observations is

\sum x_i=2.79\:+2.57+\:2.73\:+3.75\:+2.27+\:2.75+\:4.00+\:4.22+\:3.88+\:4.35+\:3.41+\:4.57+\:2.38+\:3.73\:+2.75+\:3.47+\:3.06\\\\\sum x_i=56.68

and the sum of their squares is

\sum x_i^2=2.79^2\:+2.57^2+\:2.73^2\:+3.75^2\:+2.27^2+\:2.75^2+\:4.00^2+\:4.22^2+\:3.88^2+\:4.35^2+\:3.41^2+\:4.57^2+\:2.38^2+\:3.73^2\:+2.75^2+\:3.47^2+\:3.06^2\\\\\sum x_i^2=197.46

(b)

The sample variance, denoted by s^2, is given by

s^2=\frac{S_{xx}}{n-1}

where S_{xx} =\sum x_i^2-\frac{(\sum x_i)^2}{n}

Applying the above formula we get that

S_{xx}=197.46-\frac{(56.68)^2}{17}\\\\S_{xx} =8.482

s^2=\frac{8.482}{17-1}=0.530

The sample standard deviation, denoted by <em>s</em>, is the (positive) square root of the variance:

s=\sqrt{s^2}

Applying the above formula we get that

s=\sqrt{0.530}=0.728

3 0
3 years ago
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