We can set up an equation to solve this problem. I am setting the number of marbles in a red jar to R.
R + R + R - 16 = 41
We solve this by adding 16 to both sides and combining all of the R terms.. This gives us:
3R = 57
We can finish this problem by dividing both sides by 3.
R = 19. So, there are 19 marbles in a red jar.
We can easily figure out how many marbles are in a blue jar by subtracting the total amount of marbles in 2 red jars from the total amount of marbles. I am setting the amount of marbles in a blue jar to B.
41 - 19*2 = B
B = 3
So, there are 3 marbles in a blue jar and 19 marbles in a red jar.
When a linear equation is in the form y = mx + c, the c, or constant, is the intercept on the y axis, meaning it crosses the y axis at (0, 1).
The gradient (1/3 in this case) is how much the y increments (or decrements) per increase of 1 of the value of x.
This would mean that there would be one point at (0, 1), and another at (3, 2). Draw a line from these two points and beyond, and that is the graph sketched.
Answer:
The length of the building's shadow = 550.66 ft
Explanations:
The height of the Empie State Building = 1250 feet
The friend's height = 75 inches
The length of the friend's shadow = 33 inches
![\frac{Actual\text{ height of the friend}}{\text{Length of the friend's shadow}}=\text{ }\frac{Height\text{ of the building}}{\text{Length of the building's shadow}}](https://tex.z-dn.net/?f=%5Cfrac%7BActual%5Ctext%7B%20height%20of%20the%20friend%7D%7D%7B%5Ctext%7BLength%20of%20the%20friend%27s%20shadow%7D%7D%3D%5Ctext%7B%20%7D%5Cfrac%7BHeight%5Ctext%7B%20of%20the%20building%7D%7D%7B%5Ctext%7BLength%20of%20the%20building%27s%20shadow%7D%7D)