Answer:
![12y+x-12=0](https://tex.z-dn.net/?f=12y%2Bx-12%3D0)
Step-by-step explanation:
If I'm not mistaken by the question, we have
![x+4y=\dfrac{2}{3}x+4](https://tex.z-dn.net/?f=x%2B4y%3D%5Cdfrac%7B2%7D%7B3%7Dx%2B4)
Multiply through by the LCM of all the denominators to clear the fractions. Since we have only one fraction, we multiply through by its LCM (3)
![3\timesx+3\times4y=3\times\dfrac{2}{3}x+3\times4](https://tex.z-dn.net/?f=3%5Ctimesx%2B3%5Ctimes4y%3D3%5Ctimes%5Cdfrac%7B2%7D%7B3%7Dx%2B3%5Ctimes4)
![3x+12y=2x+12](https://tex.z-dn.net/?f=3x%2B12y%3D2x%2B12)
Putting all terms on the LHS (left hand side) and evaluating,
![12y+x-12=0](https://tex.z-dn.net/?f=12y%2Bx-12%3D0)
can you please add the answers to choose from? I'd like to help
The best definition for the term substitution would be...
the action of replacing someone or something with another person or thing.