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sweet [91]
3 years ago
11

The initial quantity at T= 0 is 1000z the quantity grows by a factor 3%. What is the quantity at T=5?

Mathematics
1 answer:
fgiga [73]3 years ago
8 0

Answer:

1,159

Step-by-step explanation:

1000*(1.03) = 1159.274 at t = 5

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Give the domain and range of the relation.
Alex_Xolod [135]

Answer:

Please check the explanation.

Step-by-step explanation:

Finding Domain:

We know that the domain of a function is the set of input or argument values for which the function is real and defined.

From the given graph, it is clear that the starting x-value of the line is x=-2, the closed circle at the starting value of x= -2 means the x-value x=-2 is included.

And the line ends at the x-value x=1 with a closed circle, meaning the ending value of x=1 is also included.

Thus, the domain is:

D: {-2, -1, 0, 1}       or    D: −2 ≤ x ≤ 1

Finding Range:

We also know that the range of a function is the set of values of the dependent variable for which a function is defined

From the given graph, it is clear that the starting y-value of the line is y=0, the closed circle at the starting value of y = 0 means the y-value y=0 is included.

And the line ends at the y-value y=2 with a closed circle, meaning the ending value of y=2 is also included.

Thus, the range is:

R: {0, 1, 2}   or    R: 0 ≤ y ≤ 2

7 0
3 years ago
Write 4 numbers that round to 700,000 when rounded to the nearest hundred thousand
enot [183]
Well off the top of my head, (700,001),(700,002),(700,003), and (700,004) are 4 numbers that round to 700,00 when rounded to the nearest hundred thousand. But if you're looking for something a little more unique, then any number from 650,000 to 749,999 would round to to 700,000 when rounded to the nearest hundred thousand. I hope this helps!
4 0
3 years ago
93% of what number is 25?​
marta [7]

Answer: The answer is 327

Explanation: 93×100/25 = 327

6 0
3 years ago
2/3(3/5x+9)=1/2(2x+40)<br><br> I posted this before but w/o the 1/2 on accident
andriy [413]
The answer and working are shown in the photo below
5 0
2 years ago
A helicopter flew north 325 meters and then flew east 500 meters. How far is the helicopter from its starting point?
kati45 [8]

Answer:

596.34m approx

Step-by-step explanation:

Given data

Let the Starting point be x

A helicopter flew north 325 meters from x

Then flew east 500 meters

Let us apply the Pythagoras theorem to solve for the resultant which is the distance from the starting position

x^2= 325^2+500^2

x^2=105625+250000

x^2= 355625

x= √355625

x=596.34m

Hence the distance from the starting point is 596.34m approx

8 0
3 years ago
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