Answer:
7
Step-by-step explanation:
Answer: 2 miles per hour
Step-by-step explanation:
Given:
The rate of interest on three accounts are 7%, 8%, 9%.
She has twice as much money invested at 8% as she does in 7%.
She has three times as much at 9% as she has at 7%.
Total interest for the year is $150.
To find:
Amount invested on each rate.
Solution:
Let x be the amount invested at 7%. Then,
The amount invested at 8% = 2x
The amount invested at 9% = 3x
Total interest for the year is $150.

Multiply both sides by 100.


Divide both sides by 50.


The amount invested at 7% is
.
The amount invested at 8% is

The amount invested at 9% is

Therefore, the stockbroker invested $300 at 7%, $600 at 8%, and $900 at 9%.
Answer:
His final score was -11 points
Step-by-step explanation:
27 - 53 = -26
-26 + 15 = -11
9the equation of a line in ' slope- intercept form ' is
y = mx + c ( m is the slope and c the y-intercept )
y = 3x + 1 is in this form
with slope = 3 and y-intercept = 1
the graph crosses the y- axis at ( 0, 1 )
from this point moving 3 units vertically up and 1 unit horizontally right gives the point (1, 4 ) . Repeating this gives the point (2, 7 )
Plot the points (0, 1 ), (1, 4 ) and (2, 7 )
Draw a straight line through them for graph of y = 3x + 1