Angles 4 and 6 are called Alternate Exterior Angles
Step-by-step explanation:
Alternate Exterior Angles are a pair of angles on the outer side of the each of two lines but on opposite sides of the transversal.
When we take two parallel lines they will create 8 angles, such as 1,2,3,4,5,6,7 & 8.
In that angle 6 is 65 degrees.
Angles 1,2,3 & $ are in one line and remaining four angles on other line.
So Angles 4 and 6 are alternate exterior angles.
Slope = (y2 - y1)/(x2 - x1) = (-1 - 17)/(-8 - (-10)) = -18/(-8 + 10) = -18/2 = -9
7.77777777 repeating
Irrational numbers are:
Numbers that repeat
7.7777777 repeats the number 7 after the decimal
Numbers that CANNOT be written as a simple fraction.
7.7777777 cannot be written as a fraction in simplest form.
Answer = 7.777777777 repeating
~Aamira~
Hope this helped :)
Answer:
Option C
Step-by-step explanation:
Exteriore angle property: Exterior angle equals the sum of opposite interior angles.
∠I = 77° + 56°
= 133°
Answer:
The function for the outside temperature is represented by ![T(t) = 85\º + 15\º \cdot \sin \left[\frac{t-6\,h}{24\,h} \right]](https://tex.z-dn.net/?f=T%28t%29%20%3D%2085%5C%C2%BA%20%2B%2015%5C%C2%BA%20%5Ccdot%20%5Csin%20%5Cleft%5B%5Cfrac%7Bt-6%5C%2Ch%7D%7B24%5C%2Ch%7D%20%5Cright%5D)
, where t is measured in hours.
Step-by-step explanation:
Since outside temperature can be modelled as a sinusoidal function, the period is of 24 hours and amplitude of temperature and average temperature are, respectively:
Amplitude
Mean temperature
Given that average temperature occurs six hours after the lowest temperature is registered. The temperature function is expressed as:
![T(t) = \bar T + A \cdot \sin \left[2\pi\cdot\frac{t-6\,h}{\tau} \right]](https://tex.z-dn.net/?f=T%28t%29%20%3D%20%5Cbar%20T%20%2B%20A%20%5Ccdot%20%5Csin%20%5Cleft%5B2%5Cpi%5Ccdot%5Cfrac%7Bt-6%5C%2Ch%7D%7B%5Ctau%7D%20%5Cright%5D)
Where:
- Mean temperature, measured in degrees.
- Amplitude, measured in degrees.
- Daily period, measured in hours.
- Time, measured in hours. (where t = 0 corresponds with 5 AM).
If , and 
, the resulting function for the outside temperature is:
