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Alex73 [517]
3 years ago
5

The table shows the height of the water in a swimming pool every 4 hours while it leaked,

Mathematics
2 answers:
blsea [12.9K]3 years ago
4 0

Answer:

3 cm per hour.

Step-by-step explanation:

180-168= 12, which means 12 cm is gone every 4 hours. To find every hour, we simply do 12 divided by 4, getting 3, which means 3 cm decreases every hour.

mr Goodwill [35]3 years ago
3 0
I think it’s between C or B for me i’ve ran into this question before but i forgot which one i picked although i did get it correct sorry i forgot
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gogolik [260]

Answer:

trade policies in order for a city-states to have a strong economy?

Step-by-step explanation:

8 0
3 years ago
Identify the vertex (the 2 beside the "x" means squared) <br><br> y=-x2 + 18x - 72
myrzilka [38]

Answer:

Write the problem as a mathematical expression.

y=−x²+18x−72

Rewrite the equation in vertex form.

y=−(x−9)²+9

Use the vertex form, y=a(x−h)2+k , to determine the values of a, h, and k.

a=−1

h=9

k=9

Find the vertex (h,k).

(9,9)

Good Luck !

Step-by-step explanation:

6 0
3 years ago
The Venn diagram shows how many of the employees at a bookstore speak Spanish, Chinese, and Russian.
Lostsunrise [7]

Answer:

The correct answer is D: 28

8 0
3 years ago
Read 2 more answers
Solve the following equation by completing the square. 3x^2-3x-5=13
mr Goodwill [35]

we'll start off by grouping some

\bf 3x^2-3x-5=13\implies (3x^2-3x)-5=13\implies 3(x^2-x)-5=13 \\\\\\ 3(x^2-x)=18\implies (x^2-x)=\cfrac{18}{3}\implies (x^2-x)=6\implies (x^2-x+~?^2)=6

so we have a missing guy at the end in order to get the a perfect square trinomial from that group, hmmm, what is it anyway?

well, let's recall that a perfect square trinomial is

\bf \qquad \textit{perfect square trinomial} \\\\ (a\pm b)^2\implies a^2\pm \stackrel{\stackrel{\text{\small 2}\cdot \sqrt{\textit{\small a}^2}\cdot \sqrt{\textit{\small b}^2}}{\downarrow }}{2ab} + b^2

so we know that the middle term in the trinomial, is really 2 times the other two without the exponent, well, in our case, the middle term is just "x", well is really -x, but we'll add the minus later, we only use the positive coefficient and variable, so we'll use "x" to find the last term.

\bf \stackrel{\textit{middle term}}{2(x)(?)}=\stackrel{\textit{middle term}}{x}\implies ?=\cfrac{x}{2x}\implies ?=\cfrac{1}{2}

so, there's our fellow, however, let's recall that all we're doing is borrowing from our very good friend Mr Zero, 0, so if we add (1/2)², we also have to subtract (1/2)²

\bf \left( x^2 -x +\left[ \cfrac{1}{2} \right]^2-\left[ \cfrac{1}{2} \right]^2 \right)=6\implies \left( x^2 -x +\left[ \cfrac{1}{2} \right]^2 \right)-\left[ \cfrac{1}{2} \right]^2=6 \\\\\\ \left(x-\cfrac{1}{2} \right)^2=6+\cfrac{1}{4}\implies \left(x-\cfrac{1}{2} \right)^2=\cfrac{25}{4}\implies x-\cfrac{1}{2}=\sqrt{\cfrac{25}{4}} \\\\\\ x-\cfrac{1}{2}=\cfrac{\sqrt{25}}{\sqrt{4}}\implies x-\cfrac{1}{2}=\cfrac{5}{2}\implies x=\cfrac{5}{2}+\cfrac{1}{2}\implies x=\cfrac{6}{2}\implies \boxed{x=3}

6 0
3 years ago
A local service agency hires you to estimate the average annual income of all 700 families living in a four square block section
Digiron [165]

Answer:

The true estimate of  the average annual income of all 700 families living in a four square block section lies within the 92% confidence interval below

   34854.3  <  \mu < 35 745.7

Step-by-step explanation:

From the question we are told that

    The  sample size is  n =  50  

    The sample mean is \= x = \$ 35300

     The population standard deviation is  \sigma =  \$ 1800

From the question we are told the confidence level is  92% , hence the level of significance is    

      \alpha = (100 - 92 ) \%

=>   \alpha = 0.08

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.751

Generally the margin of error is mathematically represented as  

      E = Z_{\frac{\alpha }{2} } *  \frac{\sigma }{\sqrt{n} }

=>   E = 1.751  *  \frac{1800 }{\sqrt{50} }

=>   E =  445.7

Generally 92% confidence interval is mathematically represented as  

      \= x -E <  \mu <  \=x  +E

=> 35 300 -445.7 <  \mu < 35 300 + 445.7

=> 34854.3  <  \mu < 35 745.7

So the true estimate of  the average annual income of all 700 families living in a four square block section lies within the 92% confidence interval

3 0
3 years ago
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