X^2 - 4x - 77 = 0 Factor and check
1 answer:
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Answer:
We conclude that
- The angle ∠1 = x = 36°
- The angle ∠2 = 4x = 4(36°) = 144°
Step-by-step explanation:
Given
<1 and <2 form a linear pair
m∠1 = 4m∠2
To determine
Find the measure of each of the two angles.
<u>Important Points about linear pair:</u>
- We know that when two lines meet or intersect, we get a linear pair of angles.
- Linear pairs are basically two adjacent angles that form a line.
- The measure of two adjacent angles forming a straight line is 180, meaning they are supplementary.
As
<1 and <2 form a linear pair
m∠1 = 4m∠2
In other words, angle 1 is 4 times the measure of angle ∠2.
Let the angle ∠1 be = x
As the angle 1 is 4 times the measure of angle ∠2, so
The angle 2 will be = 4x
As <1 and <2 forms a linear pair, thus the measure of the sum of <1 and <2 will be 180°, so
divide both sides by 5
Thus, we conclude that
- The angle ∠1 = x = 36°
- The angle ∠2 = 4x = 4(36°) = 144°
Answer:
Given: The following system:
4x + y − 2z=18 ......[1]
2x-3y+3z = 21 ......[2]
x-3y=6 ......[3]
we can write equation [3] as;
3y = x-6 ......[4]
Multiply by 3 in equation [1] to both sides of an equation we get,
or
12x+3y-6z=54 ......[5]
Substituting the equation [4] in [2] and [5] we get;
2x-(x-6)+3z=21 or
2x-x+6+3z=21
Simplify:
x+3z=15 .....[6] [combine like terms]
12x+x-6-6z =54
Simplify:
13x-6z=60 ......[7] [Combine like terms]
On Solving equation [6] and [7] simultaneously,
x+3z=15
13x-6z=60
we get the value of x
i.e, x=6
Substitute the value of x in equation x+3z=15 we get
6+3z=15 or
3z=9
Simplify:
z=3
Also, substitute the value of x=6 in equation [3] we get the value of y;
x-3y=6
6-3y=6 or
-3y = 0
Simplify:
y = 0
Therefore, the solution to the system of three linear equation is, (6, 0 , 3)