Answer:
MATLAB code is given below
Explanation:
% Define the function.
function [ output_args] = removeEvens( input_args)
%UNTITLED Summary of this function goes here
% Detailed explanation goes here
%Remove the even number from the array using mod function.
output_args = input_args (mod(input_args,2)~=0);
%Display the message.
disp('odd Values are');
%Display the results.
disp(output_args);
%Terminate the function.
end
Function Call:
%Function Call
inputRowArray = [1,2,3,4,5]
removeEvens(inputRowArray)
Answer:
The answer is the "TO address"
Explanation:
i just took the test and got it right sooooooo
Answer:
Explanation:
When I think about computers, I can understand about the software and the hardware, we can touch the hardware, but the software don't because is only data stored in the hardware, we can interact with the stored data using the hardware, we can complete a system with data, software, hardware, and people, people try to learn about software because it is better paid than fix a hardware.
Answer:
"double result=6.759;" is the correct answer for the above question.
Explanation:
- In c-programming language, the double is a data type which stores the decimal value up to 6 decimal point.
- This data type takes 8 bytes space in memory when it is used in the c-programming language.
- When the user wants to declare the double data type, then he should need to declare by the help of the following syntax-- double variable_name_or _identifier_name;
- When the user wants to declare the double data type and initialize the value on its then he can do this with the help of the following syntax--double variable_name_or _identifier_name= value_which_needs_to_store;
- The above question asked the one-line statement which declares the result variable of double data type and initializes the "6.759" value on its then he can do this by the help of "double result=6.759;" statement which is described above. Hence the answer is "double result=6.759;".
