Question

Show solving steps for x^2-10x +4=12

Answer 1

Answer:

Step-by-step explanation:

We are given

$x^2 - 10x + 4 = 12$

get it all to one side equaling zero

$x^2 - 10x - 8 = 0$

now, we want to find the factors of 8 that either add up to of have a difference of 10

Factors of 8:

$1, 8, 2, 4$

None of the factor pairs add up to or have a difference of 10.

So, we can use the quadratic formula

$x = \frac{-b\pm\sqrt{b^2-4ac} }{2a} \\x = \frac{10\pm\sqrt{100-4*8} }{2}\\x = \frac{10\pm\sqrt{132} }{2}\\\\\\x = \frac{10 + \sqrt{132} }{2}= 10.74456265\\x = \frac{10 - \sqrt{132} }{2} = -0.7445626465$