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3 years ago

Why do we use coordinate planes to do transformations and dilations?

Mathematics

1 answer:

gogolik [260]3 years ago

7 0

Answer: a coordinate plane is used in order to track the location of the object.

Translations are congruence transformations that move an object, without changing its size or shape

Dilations are transformations that generate an enlargement

Step-by-step explanation:

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Someone please help I'll give brainliest for questions 11 and 12

Nostrana [21]

Answer:

Step-by-step explanation:

11.

to find floor area:

= 8 x 8

= 64

= Floor is 64m.

to find carpet: 8 x 8 x 75%

= 64 x 75%

= 64 x 0.75

= 48

a. The dimensions of the carpet are probably 8 by 8.

b. The area of the floor not covered by carpet is 64, hence 8 x 8.

12.

A perfect square is a square that has demensions that is a number multiplied by itself.

Eight times eight fits the requirements, so this square is in fact perfect.

Have a lovely day!

4 0

3 years ago

Race car driver Mario won 3 races and earn 75 points for each win. During the fourth race, he had dedications of 55 points, 104

svet-max [94.6K]

Answer:

he has 472 points now.

Step-by-step explanation:

5 0

4 years ago

Please help, need for math hw and cant figure it out

swat32

The standard form of the quadratic function f(x) = -3x^2 + 6x - 2 is f(x) = -3x^2 + 6x - 2

<h3>How to represent the quadratic function in standard form?</h3>

The quadratic function is given as

f(x) = -3x^2 + 6x - 2

The standard form of a quadratic function is represented as:

f(x) = ax^2 + bx + c

When both equations are compared, we can see that the function f(x) = -3x^2 + 6x - 2 is already in standard form

Where

a = -3

b = 6

c = -2

Hence, the standard form of the quadratic function f(x) = -3x^2 + 6x - 2 is f(x) = -3x^2 + 6x - 2

Read more about quadratic function at

brainly.com/question/25841119

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7 0

1 year ago

(a-2)^2=64 <br> Please help solve?

Ann [662]

Answer:

Step-by-step explanation:

a=10

8 0

2 years ago

Read 2 more answers

A recent study found that the average length of caterpillars was 2.8 centimeters with a

pogonyaev

Using the normal distribution, it is found that there is a 0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

In this problem, the mean and the standard deviation are given, respectively, by:

$\mu = 2.8, \sigma = 0.7$ .

The probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters is <u>one subtracted by the p-value of Z when X = 4</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{4 - 2.8}{0.7}$

Z = 1.71

Z = 1.71 has a p-value of 0.9564.

1 - 0.9564 = 0.0436.

0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

More can be learned about the normal distribution at brainly.com/question/24663213

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4 0

2 years ago