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tiny-mole [99]
4 years ago
9

Find two solutions of the equation 3X plus 5Y equals to 0

Mathematics
1 answer:
Natalka [10]4 years ago
4 0

Answer:

The two solutions can be

1st \: solution \\ x \:  =  - 5 \\ and \: \\ y\:  =  \:  - 3

2nd \:  solution  \\ x = 0 \\ and \\ y = 0

<em><u>Hop</u></em><em><u>e</u></em><em><u> this</u></em><em><u> helps</u></em><em><u> you</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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Which of the following is NOT true? Question 19 options: (3x2y5)3=27x6y15 (1000x12y20z−3)0=1 52‾‾√3=523 42×43= 165
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Answer:


Step-by-step explanation:

Lets try to simplify each to check which one is incorrect so it will be NOT true

first one is :

distribute the exponent so :

(3x^2y^5)^3 =3^3x^{2*3}y^{5*3}

27x^6y^{15} CORRECT

Second one is :

(1000x^{12}y^{20}z^{-30})^{0} =1

CORRECT because anything raised to exponent 0 is 1 .

Last one is :

4^2 *4^3 = 4^{2+3}\\=4^{6}\\=(4)^{2*3}\\=16^{3}

so Last is<em> INCORRECT</em>



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