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2 years ago

Five lemons cost 1.80. At this rate, what is the cost of 10 lemons?

Mathematics

2 answers:

kupik [55]2 years ago

8 0

Answer: 3.60

Step-by-step explanation:

Just multiply 1.80 *2 because the number of lemons are doubled.

7nadin3 [17]2 years ago

6 0

$3.60, 5 x 2 = 10. So 1.80 x 2 = 3.60

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If f(x)=5x+1 and g(x)=2f(x)+5 then g(-1)=

ollegr [7]

We know f(x)=5x+1. Plug in f(x) in the g(x) function.
We get $g(x)=2(5x+1)+5$ Distribute the 2 to 5x and 1.
$g(x)=10x+2+5$
Simplify to get $g(x)=10x+7$
Now, we plug in -1 for x.
$g(-1)=10(-1)+7$
$g(-1)=-10+7$
$g(-1)=-3$

4 0

2 years ago

Can somebody help me on this and if so please answer correctly

mrs_skeptik [129]

The answer is A. Good luck man!! :)

4 0

2 years ago

Two cyclists leave city at same time, one going east and the other going west. The westbound cyclist bikes 3 mph faster than the

Bumek [7]

Speed of the east bound cyclist is 12 mph and the speed of west bound cyclist is 15 mph.

<u>Solution:</u>

Let us assume that x is speed of slower eastbound cyclist

So, x+3 will be the speed of faster westbound cyclist

We know that distance is the product of speed and time. That is,

$\text{Distance}=\text{Speed}\times\text{Time}$

West-bound DATA:

Rate of speed = x+3 mph ; Time = 6 hrs ; distance = 6(x+3) = 6x+18 miles

East-bound DATA:

Rate of speed = x mph ; time = 6 hrs. ; distance = 6x miles

On solving,

Distance apart = 162

$\Rightarrow6x+18+6x = 162$

$\Rightarrow12x=162-18$

$\Rightarrow x=\frac{144}{12}\rightarrow x=12$

So, the rate of speed of the east bound cyclist is 12 mph and the rate of speed of the west bound cyclist will be $x+3=12+3=15 \text{ mph}$

8 0

2 years ago

The realtor and her clients do not know the average home sale price for all of Guelph (500 was actually just a guess). However,

strojnjashka [21]

Answer:

a) The 99% confidence interval would be given by (346.708;453.292)

b) The 99% confidence interval would be given by (338.445;461.555)

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=400$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=80$ represent the population standard deviation

n=15 represent the sample size

2) Part a

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that $z_{\alpha/2}=2.58$

Now we have everything in order to replace into formula (1):

$400-2.58\frac{80}{\sqrt{15}}=346.708$

$400+2.58\frac{80}{\sqrt{15}}=453.292$

So on this case the 99% confidence interval would be given by (346.708;453.292)

3) Part b

For this case we don't know the population deviation so we need to use the t distribution instead the normal standard distribution.

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

We need to find the degrees of freedom first df=n-1=15-1=14

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,14)".And we see that $t_{\alpha/2}=2.98$

Now we have everything in order to replace into formula (1):

$400-2.98\frac{80}{\sqrt{15}}=338.445$

$400+2.98\frac{80}{\sqrt{15}}=461.555$

So on this case the 99% confidence interval would be given by (338.445;461.555)

4 0

2 years ago

The ratio of girls to students at a middle school is 10 to 18. If there are 270 students at the school, how many are girls?

Stells [14]

A good way of doing this problem would be to use cross multiplication of ratios
<u /> $\frac{10 girls}{18 students} = \frac{X girls}{270 students}$

Then cross multiply

(10 girls)(270 students)=(X girls)(18 students)

2700=18x
150=x

4 0

3 years ago

Read 2 more answers