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Digiron [165]
3 years ago
8

D = 8 cm h = 18 cm What is the surface area of the cylinder

Mathematics
1 answer:
mars1129 [50]3 years ago
5 0

Answer:

144 (If multiplying)

Step-by-step explanation:

18x8=144.

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What is 1-cos(6x)=___
FromTheMoon [43]

Answer:

2sin^2(3x)

Step-by-step explanation:

3 0
3 years ago
TYPES OF CARS WORKED ON German cars 25% Other 10% American 50% Japanese 15% These are the types of cars worked on in the auto se
lukranit [14]

Answer:

<h2>6) 40%</h2><h2>7) 900 cars</h2>

Step-by-step explanation:

German  25%

Other 10%

American 50%

Japanese 15%

……………………………………………

6) the probability that the next car worked on

will be Japanese or German :

p(J∪G) = p(J) + p(G) = 15% + 25% = 40%.

…………………………………………………………

7) the probable number of Japanese cars :

6000\times \frac{15}{100} = 900

3 0
2 years ago
Suppose that 500 parts are tested in manufacturing and 10 are rejected.
alexdok [17]

Answer:

a) z=\frac{0.02 -0.03}{\sqrt{\frac{0.03(1-0.03)}{500}}}=-1.31  

p_v =P(Z  

If we compare the p value obtained and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of rejected items is less than 0.03.  

b) We can use a 95 percent upper confidence interval.

On this case we want a interval on this form : (-\infty,\hat p +z_{\alpha}\sqrt{\frac{\hat p (1-\hat p)}{n}})

So the critical value would be on this case Z_{\alpha}=1.64 and we can use the following excel code to find it: "=NORM.INV(1-0.05,0,1)"

We found the upper limit like this:

0.02+1.64\sqrt{\frac{0.02 (1-0.02)}{500}}=0.03026

And the interval would be: (-\infty,0.03026)

And since our value (0.02) is contained in the interval We fail to reject the hypothesis that p=0.03

Step-by-step explanation:

Part a

Data given and notation  

n=500 represent the random sample taken

X=10 represent the number of objects rejected

\hat p=\frac{10}{500}=0.02 estimated proportion of objects rejected

p_o=0.03 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that 70% of adults say that it is morally wrong to not report all income on tax returns.:  

Null hypothesis:p=0.03  

Alternative hypothesis:p < 0.03  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.02 -0.03}{\sqrt{\frac{0.03(1-0.03)}{500}}}=-1.31  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a one tailed left test the p value would be:  

p_v =P(Z  

If we compare the p value obtained and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of rejected items is less than 0.03.  

Part b

We can use a 95 percent upper confidence interval.

On this case we want a interval on this form : (-\infty,\hat p +z_{\alpha}\sqrt{\frac{\hat p (1-\hat p)}{n}})

So the critical value would be on this case Z_{\alpha}=1.64 and we can use the following excel code to find it: "=NORM.INV(1-0.05,0,1)"

We found the upper limit like this:

0.02+1.64\sqrt{\frac{0.02 (1-0.02)}{500}}=0.03026

And the interval would be: (-\infty,0.03026)

And since our value (0.02) is contained in the interval We fail to reject the hypothesis that p=0.03

3 0
3 years ago
54 out of 90 people have a cat. What percent of people have a cat?
AveGali [126]

Answer:

60% of people have a cat.

Step-by-step explanation:

That would be 54/90 times 100%, or 60%

60% of people have a cat.

3 0
3 years ago
Please help
lisov135 [29]

Answer: 12

Step-by-step explanation:

law of cosines states that f^2 = t^2 + p^2 - 2tp cos(F)

so f^2 = 5^2 + 7^2 - 2*5*7*cos(175)

f^2 = 74 - (-69.7336)

f^2 = 143.7336

f = 11.9889

which rounds to 12

7 0
3 years ago
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