Answer this please!!!!!!
1 answer:
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Answer:
We readily separate the variables and integrate:
∫dP/P=∫(k+bcos2t)dt
ln P=kt+(b/2)*sin2
t+ln C
Clearly C = Po, so we find that P(t) = Poexp(kt + (b/2)* sin 2
t). The 271- curve with the typical numerical values P_o = 100, k = 0.03, and b = 0.06. It oscillates about the curve which represents natural growth with P_o and k = 0.03. We see that the two agree at the end of each full year.
note:
find the attached graph
Answer:
Step-by-step explanation:
I would begin by distributing the L. It will be easier in the end to do it this way. There are a couple of ways you can do this, but distribution is the easiest. After you distribute the L you have
T = 2L + LRS
Next subtract the 2L to get
T - 2L = LRS. Lastly, to isolate the R, divide away the LS to get
= R In that second term, the L's cancel each other out, leaving us with
= R