Which model represents the equation 4r = 24
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There is no absolute value function when graphed, will be wider than the graph of the parent function f(x) = |x|
<h3>What is an absolute value function?</h3>An absolute value function is a function such that,
For the given example,
We have been given a parent function f(x) = |x|
We need to find the absolute value function, when graphed, will be wider than the graph of the parent function.
Consider the graph of all absolute value functions.
The graph of f(x) = |x| + 3 is represented blue color.
The graph of f(x) = |x − 6| is represented green color.
The graph of f(x) = |x| is represented red color.
The graph of f(x) = 9|x| is represented violet color.
From this graph, we can observe that,
f(x) = |x| + 3 is as wise as the parent absolute value function f(x) = |x| translated up by 3 units.
Similarly, the function f(x) = |x - 6| is as wise as the parent absolute value function f(x) = |x| translated right by 6 units.
This means, there is no absolute value function when graphed, which will be wider than the graph of the parent function f(x) = |x|
Learn more about the absolute value function here:
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One way to figure this out is to you can set up two equivalent fraction problems to figure out in both cases how many times the adult and twelve year old each blink in 60 minutes.
Adult blinks:
Child blinks:
In the "adult blinks" problem, you know that 30 is half of 60 - you can then multiply the numerator 450 x 2 to get 900 blinks per 60 min.
In the "child blinks" problem, 15 is one-quarter of 60, so you can multiply the numerator 150 x 4 to get 600 blinks per 60 min.
You can then just subtract the two new numerators, 900 - 600, to find that the adult blinks 300 more times than the 12-year-old in 60 minutes.
Adult blinks:
Child blinks:
In the "adult blinks" problem, you know that 30 is half of 60 - you can then multiply the numerator 450 x 2 to get 900 blinks per 60 min.
In the "child blinks" problem, 15 is one-quarter of 60, so you can multiply the numerator 150 x 4 to get 600 blinks per 60 min.
You can then just subtract the two new numerators, 900 - 600, to find that the adult blinks 300 more times than the 12-year-old in 60 minutes.