Question

I AM GIVING BRAINLISEST AND 20 POINTS! Write the equation of the circle in standard form.

Answer 1

Answer:

$(x-4)^2+(y)^2=1$

Step-by-step explanation:

The general format for the equation of a circle is the following:

$(x-n)^2+(y-m)^2=1$

This circle will have its center at point $(n,m)$. Please note that its center is shifted (n) units to the right of the origin, and (m) units up. Apply this knowledge to the given problem.

The circle in the given problem has its center at (4, 0). Therefore the following can be stated,

$n=4\\\\m =0$

Substitute these points into the general formula for the equation of a circle, then simplify,

$(x-n)^2+(y-m)^2=1$

$(x-4)^2+(y-0)^2=1$

$(x-4)^2+(y)^2=1$