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ololo11 [35]
3 years ago
10

Transformation can you help ?

Mathematics
1 answer:
Lemur [1.5K]3 years ago
8 0
To go from the original to number I you need to do a reflection across the y-axis.  To go from I to II you need to do a 90 degree clockwise rotation about the origin.
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Miguel did the following math problem: 65 ∙ 64 = 369. Which of the following is a true statement
alexdok [17]
C. is the answer to the question
4 0
3 years ago
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Andrea is buying some new shirts and sweaters. She is able to buy 3 shirts and 2 sweaters for $114, or she is able to buy 2 shir
OLEGan [10]

Answer:

The cost of a shirt is $16 and the cost of a sweater is $33

Step-by-step explanation:

Let

x -----> the cost of a shirt

y -----> the cost of a sweater

we know that

3x+2y=114 -----> equation A

2x+4y=164----> equation B

Solve the system by graphing

Remember that the solution of the system is the intersection point both graphs

The solution is the point (16,33)

see the attached figure

therefore

The cost of a shirt is $16 and the cost of a sweater is $33

4 0
3 years ago
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Need fast for a retest
Stells [14]
Not sure about this one
7 0
3 years ago
Name a pair of opposite rays in the diagram above. (There is more than one possible answer)
77julia77 [94]

Perpendicular. Only because its 2 lines that intersect one another.


6 0
3 years ago
X and Y are both standard normal random variables (mean = 0, standard deviation = 1), statistically independent of each other. U
Dvinal [7]

Answer:

The probability that X and Y are both positive and that their sum is less or equal to 1 0.64.

Step-by-step explanation:

It is provided that the random variables <em>X</em> and <em>Y </em>follows a standard normal distribution.

That is, X,Y\sim N(0, 1)

It is also provided that the variables <em>X</em> and <em>Y </em>are statistically independent of each other.

Compute the probability that X and Y are both positive and that their sum is less or equal to 1 as follows:

The mean and standard deviation of <em>X</em> + <em>Y</em> are:

E(X+Y)=E(X)+E(Y)=0+0=0\\\\SD(X+Y)=\sqrt{V(X)+V(Y)+2Cov(X,Y)}=\sqrt{1+1+0}=\sqrt{2}

The probability is:

P(X+Y\leq 1)=P(X+Y

                       =P(X+Y

*Use the <em>z</em>-table.

Thus, the probability that X and Y are both positive and that their sum is less or equal to 1 0.64.

3 0
3 years ago
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