180/60 = the number of student for 1%
180/60 = 3
so 1% of the school's population is 3 students
so, 3 x 100 = 300 students
and to check:
300 x .60 = 180
so, the total population of the school is 300
Answer:
This is 0.14 to the nearest hundredth
Step-by-step explanation:
Firstly we list the parameters;
Drive to school = 40
Take the bus = 50
Walk = 10
Sophomore = 30
Junior = 35
Senior = 35
Total number of students in sample is 100
Let W be the event that a student walked to school
So P(w) = 10/100 = 0.1
Let S be the event that a student is a senior
P(S) = 35/100 = 0.35
The probability we want to calculate can be said to be;
Probability that a student walked to school given that he is a senior
This can be represented and calculated as follows;
P( w| s) = P( w n s) / P(s)
w n s is the probability that a student walked to school and he is a senior
We need to know the number of seniors who walked to school
From the table, this is 5/100 = 0.05
So the Conditional probability is as follows;
P(W | S ) = 0.05/0.35 = 0.1429
To the nearest hundredth, that is 0.14
Given that an object with a mass of 54kg travels at 15m/s^2, determine the kinetic energy of the object.
KE = 0.5 x mv^2
M (mass) = 54kg
V (velocity) = 15m/s^2
Then, we plug the values in.
KE = 0.5 x 54(15^2)
Now, we solve.
KE = 0.5 x 54(225)
KE = 0.5 x 12150
KE = 6075
Now, that we have solved the formula, we can see that the kinetic energy of the object is 6,075J.
Thus, the kinetic energy of the object is 6,075J.
The answer would be A. m= -3/5 and b=-4/5
"m= -5-1 divided by 7--3
or, -6/10
or, -3/5.
to find the (B)
<span><span>(-3,1). y=mx+b or 1=-3/5 × -3+b, or solving for b: b=1-(-3/5)(-3). b=-4/5.</span><span>(7,-5). y=mx+b or -5=-3/5 × 7+b, or solving for b: b=-5-(-3/5)(7). b=-4/5.</span></span>See! In both cases we got the same value for b. And this completes our problem.
<span><span>The equation of the line that passes through the points(-3,1) and (7,-5)is</span><span>y=-3/5x-4/5"</span>
Source: webmath</span>
