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hodyreva [135]
2 years ago
8

Please help and explain how you solved it. Thanks.

Mathematics
1 answer:
galina1969 [7]2 years ago
3 0

Answer:

This is 0.14 to the nearest hundredth

Step-by-step explanation:

Firstly we list the parameters;

Drive to school = 40

Take the bus = 50

Walk = 10

Sophomore = 30

Junior = 35

Senior = 35

Total number of students in sample is 100

Let W be the event that a student walked to school

So P(w) = 10/100 = 0.1

Let S be the event that a student is a senior

P(S) = 35/100 = 0.35

The probability we want to calculate can be said to be;

Probability that a student walked to school given that he is a senior

This can be represented and calculated as follows;

P( w| s) = P( w n s) / P(s)

w n s is the probability that a student walked to school and he is a senior

We need to know the number of seniors who walked to school

From the table, this is 5/100 = 0.05

So the Conditional probability is as follows;

P(W | S ) = 0.05/0.35 = 0.1429

To the nearest hundredth, that is 0.14

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Plug in and determine solution

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3 years ago
When an object is droppednbsp on a certain earth dash like planet comma on a certain earth-like planet, the distance it falls in
ANTONII [103]

Answer:

(a) s(44) = 3.52*10^{6}ft

(b) v(44) = 10*x^{5} ft/s

(c) a(44) = 3636ft/s^{2}

Step-by-step explanation:

s(t) = 1818t^{2}

(a) when t = 44sec

s(44) = 1818(44^{2}) = 1818(1936)\\ \\s(44) = 3519648ft

s(44) ≅ 3520000=3.52*10^{6}ft

(b) How fast the hammer is traveling i.e. the speed of the hammer.

To find speed, we differentiate the distance s(t) with respect to time, t

speed,v=\frac{ds(t)}{dt}=\frac{d}{dt}(1818t^{2})   \\\\v = 1818*2t^{2-1}= 1818*2t\\ \\v = 3636t

at t = 44sec,

v = 3636*44=159984ft/s

v ≅ 160000ft/s = 1.6*10^{5}ft/s

(c) The hammer's acceleration can be obtained by differentiating the speed v(t) with respect to time, t

acceleration, a = \frac{dv}{dt}=\frac{d}{dt}(3636t)\\  \\a = 3636*1= 3636\\\\a = 3636ft/s^{2}

There's no need to substitute t = 44sec because the acceleration is independent of time.

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