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kaheart [24]
3 years ago
13

What is the minimum value for the function shown in the graph?

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
6 0
The minimum value for the function is -6
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Two friends, Lucy and Lydia, had just bought their first cars. Lydia uses 3 gallons of gas to drive 114 miles in her car. The gr
alexandr402 [8]

Answer:

3.5 miles

Step-by-step explanation:

Lydia:

3 gallons of gas = 114 miles

We want to know how many miles a friend can travel on one gallon of gas, so we divide both sides by 3

1 gallon of gas = 114/3 miles = 38 miles

Lucy:

One point is

10x corresponds to 415y

10 gallons = 415 miles

divide both sides by 10 to get one gallon on a side

1 gallon = 41.5 miles

Lydia:

38 miles = 1 gallon

Lucy:

41.5 miles = 1 gallon

For 1 gallon, the difference is 3.5 miles, with Lydia having 3.5 miles less than Lucy.

3 0
2 years ago
If 3/2 divided by 1/4 =n , then n is between
kari74 [83]
OK, this written in numbers is

\frac{3/2}{1/4} =n

But, fractions can not divide.  So we need to multiply one by the reciprocal of the other.  The reciprocal of a fraction is itself flipped upside down.  For example, the reciprocal of 1/2 would be 2/1.  

So, we will multiply 3/2 by 4/1.  We know how to do this, it is simply 3/2*4=12/2=6.

So, the answer is n = 6.  That would be answer c, because 6 is between 5 and 7.


3 0
4 years ago
Read 2 more answers
The perimeter of a rectangle is 200 feet. Describe the possible lengths of a side if the area of the rectangle is not to exceed
slavikrds [6]
Length=x
width=y
Perimeter of a rectangle=2(length)+2(width)
Therefore:
2x+2y=200
We simplify the equation dividend both sides of this equation by 2:
x+y=100  
Then:
y=100-x

Area of a rectangle: length x width
We have the next inequation: 
x(100-x)<900
100x-x²<900
x²-100x+900<0

We solve this inequation
1) we solve this equation:
x²-100x+900=0
x=[100⁺₋√(10000-3600)]/2=(100⁺₋80)/2
We have two solutions in this equation:
x₁=90
x₂=10

2)With these values, we make intervals:
(-∞,10)
(10,90)
(90,∞)

3)With these intervals, we check it out if the inequation works: 
(-∞,10); for example; if x=0 ⇒ 0²-100(0)+900=100>0, this interval don´t work.
(10,90);f.e: if x=11; ⇒ 11²-100(11)+900=-79<0, this interval works.
(90,∞); fe; if x=91 ⇒91²-(100)91+900=81>0; this interval don´t work.

answer: the possible lengths would be the values inside of this interval:
(10,90) ft.
7 0
4 years ago
What would the length be?
Natalka [10]

Answer:

EF = ~3.8

Step-by-step explanation:

Apply the sine theorem:

EF/sinD = DE/sinF

=> EF = DE*(sinD/sinF)

         = 3*(sin75/sin50)

         =3.78 = ~3.8

Hope this helps!

4 0
4 years ago
Roger can run one mile in 6 minutes. Jeff can run one mile in 4 minutes. If Jeff gives Roger a 1 minute head start, how long wil
Lynna [10]
Roger speed 1/6 mile/min
Jeff speed 1/4 mile/min

Set Jeff catch Roger at x, time t
X= 1/6*t
X=1/4*(t-1)
=> 1/6*t=1/4(t-1)
4t=6t-6
t=3
X=1/2
4 0
4 years ago
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