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Rashid [163]
3 years ago
15

Given the function g(x)=−3x+1 find g(-6).

Mathematics
2 answers:
babymother [125]3 years ago
5 0

Answer:

g(-6) = 19

Step-by-step explanation:

g(-6) = -3(x)+1

g(-6)= -3(-6)+1 : plug in the given value for x

g(-6)= 18+1 : -3 multiplied by -6 gives you 18

g(-6)= 19

polet [3.4K]3 years ago
3 0

Answer:

g(-6)=19

Step-by-step explanation:

g(x)=-3x+1

g(-6)=-3(-6)+1

g(-6)=18+1

g(-6)=19

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Skyler would have $128.

Multiply 18 by 6 and then add 20.
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3 years ago
What does negative 2 over 7 > −4 indicate about the position of negative 2 over 7 and −4 on the number line?
jeyben [28]
-4/7 > -2

If it is greater it goes to the right, and if it is less it goes to the left.

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6 0
3 years ago
PLEASE HELP ASAP GIVING 100 POINTS
Inessa [10]

Answer:

3.98 meters

Step-by-step explanation:

First we need to know the formula for finding the height of a cylinder

h=\frac{V}{\pi r^2}

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2 years ago
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AlladinOne [14]
<h3>Answer:   7 goes in the blank space</h3>

The range of values for x is 2 < x < 7

========================================

Explanation:

The hinge theorem says that the larger the opposite side is, the larger the angle will be.

AD = 11, DC = 8

Since AD > DC, this means angle ABD > angle DBC.

--------

angle ABD > angle DBC

20 > 4x-8

20+8 > 4x-8+8 ... add 8 to both sides

28 > 4x

4x < 28 ... flip both sides and the inequality sign

4x/4 < 28/4 ... divide both sides by 4

x < 7

--------

At the same time, the angle 4x-8 cannot be 0 or negative.

So we say 4x-8 > 0. Let's solve this for x.

4x-8 > 0

4x-8+8 > 0+8 ... add 8 to both sides

4x > 8

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x > 2

2 < x ... flip both sides and the inequality sign

--------

We have 2 < x and x < 7. Both of these combine to the compound inequality 2 < x < 7

We can pick any value between 2 and 7 as long as we dont pick x = 2 or we dont pick x = 7.

6 0
3 years ago
A point is located in quadrant II of a
givi [52]

Answer:

Choose a point with a negative x coordinate and a positive y coordinate.

Step-by-step explanation:

The quadrants are labeled counter clockwise 1, 2, 3, and 4.

Quadrant I - has x and y coordinate both positive.

Quadrant 2 - has x coordinate negative and y coordinates positive.

Quadrant 3  - has x and y coordinates both negative.

Quadrant 4 - has x coordinates positive and y coordinates negative.

Since the point is in quadrant 2, choose a point where x is negative but y is positive like (-3, 2).

3 0
3 years ago
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