Answer: Okay the answer its 2304 pi
and decimal from its 7238.22947387
...
since it keeps going on. Or you could round it to the hundredth's place and get 723.8
Answer:
a) 336
b) 593775
c) 83160
d) P=0.14
e) P=0.0019
Step-by-step explanation:
We have wine supply includes 8 bottles of zinfandel, 10 of merlot, and 12 of cabernet.
a) If he wants to serve 3 bottles of zinfandel and serving order is important. We get:
C=8·7·6=336
b) {30}_C_{6}=\frac{30!}{6!(30-6)!}
{30}_C_{6}=593775
c) {8}_C_{2} · {10}_C_{2} · {12}_C_{2}=
=\frac{8!}{2!(8-2)!} · \frac{10!}{2!(10-2)!} · \frac{12!}{2!(12-2)!}
=28 · 45 · 66
=83160
d) We calculate the number of possible combinations:
{30}_C_{6}=593775
We calculate the number of favorable combinations:
{8}_C_{2} · {10}_C_{2} · {12}_C_{2}=83160
The probability that this results in two bottles of each variety being is
P=83160/593775
P=0.14
e) We calculate the number of possible combinations:
{30}_C_{6}=593775
We calculate the number of favorable combinations:
{8}_C_{6} + {10}_C_{6} + {12}_C_{6}= 28+210+924=1162
The probability is
P=1162/593775
P=0.0019
Isolate the variable by dividing each side by factors that don't contain the ...
y variable=139x/ 5 2/5-
x variable =5y/139+2/139
Answer:
Cost of 1 bushes = a = $9
Cost of 1 tree = b = $73.5
Step-by-step explanation:
Given:
13 bushes and 4 trees cost = $411
Missing;
6 bushes and 2 trees cost = $201
Find:
Value of bushes and tree
Computation:
Cost of 1 bushes = a
Cost of 1 tree = b
So,
13a + 4b = 411 ...........eq1
6a + 2b = 201 ................eq2
From Eq1 and Eq2
Cost of 1 bushes = a = $9
From eq 1
13a + 4b = 411
13(9) + 4b = 411
Cost of 1 tree = b = $73.5
Please excuse my dear aunt sally or pemdas