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3 years ago

5.1(3+2.2x)>-14.25-6(1.7x+4)

Mathematics

2 answers:

bekas [8.4K]3 years ago

8 0

Answer:

(-2.5, ∞)

Step-by-step explanation:

You can add the opposite of the right side.

5.1(3 +2.2x) +14.25 +6(1.7x +4) > 0

15.3 +11.22x +14.25 + 10.2x +24 > 0 . . . eliminate parentheses

21.42x +53.55 > 0 . . . . . . . . . . . . . . . . . . collect terms

x + 2.5 > 0 . . . . . . . . . . . . . . . . . . . . . . . . .divide by the coefficient of x

x > -2.5 . . . . . . add the opposite of the constant

KATRIN_1 [288]3 years ago

5 0

(- 2.5, ∞ )

distribute parenthesis on both sides of inequality and simplify

15.3 + 11.2x > - 14.25 - 10.2x - 24

15.3 + 11.2x > - 38.25 - 10.2x ( add 10.2x to both sides )

15.3 + 21.42x > - 38.25 ( subtract 15.3 from both sides )

21.42x > - 53.55 ( divide both sides by 21.42 )

x > - 2.5

solution x ∈ (- 2.5, ∞ )

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2 years ago

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<h2>Answer:</h2>

$6\frac{1}{2}$ <u>, "six and one over two ft".</u>

<h2>Step-by-step explanation:</h2>

Let's considerate the fact that the garden has a <u>square shape</u>.

<h3>1. Finding values of interest.</h3>

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Length of one side: $2\frac{3}{4}$ ft.

If one side measures $2\frac{3}{4}$ ft, and the square garden has 4 sides of equal length, because it's a square, then we must multiply the measure of one side by 4 to find the total length of fence needed:

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The gardener already has $4\frac{1}{2}$ , which equals $4 + \frac{1}{2}$ . Hence, the difference between the amount needed and the amount that the gardeneralready has will give us the remaining amount required. Let's do that:

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1 year ago

A package of aa batteries costs 3.50 plus an additional 6% tax. What is the price after tax?

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6 0

3 years ago

Read 2 more answers

Of 100 students,65 are members of a mathematics club and 40 are members of a physics club. if 10 are members of neither club the

alexandr1967 [171]

a. 15 students are members of both clubs

b. 50 students only are members of the mathematics club

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Step-by-step explanation:

The given is:

There are 100 students
65 are members of a mathematics club
40 are members of a physics club
10 are members of neither club

We need to find how many students are members of

a. both clubs?

b. only mathematics club

c. only physics club

∵ The total number of students = 100

∵ 10 are members of neither club

- Subtract 10 from 100 to find the members of the mathematics

club or the physics club

∵ 100 - 10 = 90

∴ There are 90 members of the mathematics club or physics club

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∵ n(mathematics) = 65

∵ 40 students are members of a physics club

∴ n(physics) = 40

∵ n(mathematics or physics) = n(mathematics) + n(physics) - n(both)

∴ 90 = 65 + 40 - n(both)

∴ 90 = 105 - n(both)

- Add n(both) to each side

∴ n(both) + 90 = 105

- Subtract 90 from each side

∴ n(both) = 15

∴ 15 students are members of both clubs

a. 15 students are members of both clubs

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∴ n(physics only) = 40 - 15 = 25

∴ 25 students only are members of the physics club

c. 25 students only are members of the physics club

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