Answer:
Step-by-step explanation:
<em>Given that X - the distribution of heights of male pilots is approximately normal, with a mean of 72.6 inches and a standard deviation of 2.7 inches.</em>
<em />
<em>Height of male pilot = 74.2 inches</em>
<em />
<em>We have to find the percentile</em>
<em />
<em>X = 74.2</em>
<em />
<em>Corresponding Z score = 74.2-72.6 = 1.6</em>
<em />
<em>P(X<174.2) = P(Z<1.6) = 0.5-0.4452=0.0548=5.48%</em>
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<em>i.e. only 5% are below him in height.</em>
<em />
<em>Thus the malepilot is in 5th percentile.</em>
Use photo math , it helps lol
Answer:
D sqrt( A ) sqrt(pi) / pi = r
Step-by-step explanation:
The area of a circle is given by
A = pi r^2
To find r
Divide each side of the equation by pi
A / pi = pi r^2 /pi
A / pi = r^2
Take the square root of each side
sqrt(A / pi )= sqrt( r^2)
sqrt(A / pi )= r
We do not like leaving square roots in the denominator, so multiply by sqrt(pi)/sqrt(pi))
sqrt(A / pi ) *sqrt(pi)/sqrt(pi))
sqrt( A ) sqrt(pi) / pi = r
Answer:
The simplified form of the expression is ![\sqrt[3]{2x}-6\sqrt[3]{x}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2x%7D-6%5Csqrt%5B3%5D%7Bx%7D)
Step-by-step explanation:
Given : Expression ![7\sqrt[3]{2x}-3\sqrt[3]{16x}-3\sqrt[3]{8x}](https://tex.z-dn.net/?f=7%5Csqrt%5B3%5D%7B2x%7D-3%5Csqrt%5B3%5D%7B16x%7D-3%5Csqrt%5B3%5D%7B8x%7D)
To Simplified : The expression
Solution :
Step 1 - Write the expression
Step 2- Simplify the roots and re-write as
and 
![7\sqrt[3]{2x}-3\times2\sqrt[3]{2x}-3\times2\sqrt[3]{x}](https://tex.z-dn.net/?f=7%5Csqrt%5B3%5D%7B2x%7D-3%5Ctimes2%5Csqrt%5B3%5D%7B2x%7D-3%5Ctimes2%5Csqrt%5B3%5D%7Bx%7D)
Step 3- Solve the multiplication
![7\sqrt[3]{2x}-6\sqrt[3]{2x}-6\sqrt[3]{x}](https://tex.z-dn.net/?f=7%5Csqrt%5B3%5D%7B2x%7D-6%5Csqrt%5B3%5D%7B2x%7D-6%5Csqrt%5B3%5D%7Bx%7D)
Step 4- Taking ![\sqrt[3]{2x}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2x%7D)
common from first two terms
![\sqrt[3]{2x}(7-6)-6\sqrt[3]{x}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2x%7D%287-6%29-6%5Csqrt%5B3%5D%7Bx%7D)
Therefore, The simplified form of the expression is
