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irakobra [83]
2 years ago
13

Polygon ABCD is a rectangle. What is its area? Round your answer to the

Mathematics
1 answer:
galben [10]2 years ago
5 0

9514 1404 393

Answer:

  26 square units

Step-by-step explanation:

Counting grid squares on the graph, we see that segment AB is the hypotenuse of a right triangle with legs 2 and 3. Its length is ...

  AB = √(2²+3²) = √13

We can also see that the adjacent longer sides are twice this length, each being the hypotenuse of a triangle that is 6 wide and 4 high.

  AC = √(6² +4²) = √52 = 2√13

Then the area is ...

  A = LW

  A = (2√13)(√13) = 2·13 = 26 . . . square units

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The answer to the math question presented above would be 10. <span>From 5 employees at a company a group of 3 employees will be chosen to work on a project, the number of different groups of 3 employees can be chosen is 10. You can have 10 different groups of threes in 5 employees.</span>
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3 years ago
Lin has 13 coins in her pocket that equal 40 cents. All the coins are dimes, d, and pennies, p. Which combination of coins does
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To answer this question you should begin with the coin that has a higher value.  If you start with the dime and then just add the correct number of pennies to total $0.40, you will see that you will need 3 dimes ($0.30) and 10 pennies ($0.10).  

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3 years ago
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4 0
3 years ago
Work out 247 as a percentage of 380.
Genrish500 [490]

Answer:

65%

Step-by-step explanation:

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2 years ago
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A bag contains 7 red and 10 white balls. In how many ways 4 balls are selected if there are more than 2 red balls? (Please solve
erastova [34]

Answer:

385 ways

Step-by-step explanation:

Given;

7 red balls

10 white balls

In how many ways can 4 balls be selected if there are more than 2 red balls.

Selecting 4 balls which must contain more than 2 red balls, will be 3 red balls and 1 white ball to make it 4 in total, or all the 4 balls selected will red balls.

= 3 red balls and 1 white ball  OR 4 red balls

= 7C₃ x 10C₁  + 7C₄

= \frac{7!}{4!3!} *\frac{10!}{9!1!} \ \ + \ \frac{7!}{3!4!} \\\\= (35*10) \ + \ 35\\\\= 350 \ + 35\\\\= 385 \ ways

Therefore, there are 385 ways of selecting 4 balls, if there are more than 2 red balls.

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3 years ago
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