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irakobra [83]
3 years ago
13

Polygon ABCD is a rectangle. What is its area? Round your answer to the

Mathematics
1 answer:
galben [10]3 years ago
5 0

9514 1404 393

Answer:

  26 square units

Step-by-step explanation:

Counting grid squares on the graph, we see that segment AB is the hypotenuse of a right triangle with legs 2 and 3. Its length is ...

  AB = √(2²+3²) = √13

We can also see that the adjacent longer sides are twice this length, each being the hypotenuse of a triangle that is 6 wide and 4 high.

  AC = √(6² +4²) = √52 = 2√13

Then the area is ...

  A = LW

  A = (2√13)(√13) = 2·13 = 26 . . . square units

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2a 2 b 3 and -4a 2 b 3 are like terms.
jolli1 [7]

Answer:

Tiger Algebra{(2a-b)^3+(a-2b)^3} - Free yet powerful Solver Simplifier that ... Step 2 : Pulling out like terms : 2.1 Pull out like factors : 9a3 - 18a2b + 18ab2 - 9b3 =Step-by-step

explanation:

3 0
3 years ago
An experiment was conducted to compare the use of iPads versus regular textbooks in teaching algebra to two classes of middle sc
lakkis [162]

Answer:

Step-by-step explanation:

Hello!

The objective is to determine if there is any difference between using iPads vs textbooks in teaching algebra.

Two middle school classes were selected, to eliminate any other source of variation, the same teacher taught both classes, and the materials were provided by the same author and publisher. After a month 10 students of each class were randomly selected and tested, their test scores were recorded:

X₁: test scores of students that used iPads to study.

n₁= 10

X[bar]₁= 86.8

S₁= 8.97

X₂: test scores of students that used regular textbooks to study.

n₂= 10

X[bar]₂= 79.5

S₂= 10.8

a.

H₀: μ₁=μ₂

H₁: μ₁≠μ₂

α:0.05

Assuming that both variables are normally distributed and the population variances are equal, the statistic to use is a Student t for two independent samples with pooled sample variance:

t_{H_0}= \frac{(X[bar]_1-X[bar]_2)-(Mu_1-Mu_2)}{Sa*\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }

Sa^2= \frac{(n_1-1)S^2_1+(n_2-1)S^2_2}{n_1+n_2-2}

Sa^2= \frac{9*80.4609+9*116.64}{10+10-2} = 98.55

Sa= 9.93

t_{H_0}= \frac{86.8-79.5}{9.93\sqrt{\frac{1}{10} +\frac{1}{10} } } = 1.64

p-value: 0.118364

The p-value is greater than the significance level so the decision is to not reject the null hypothesis. This means that there is no significant evidence between the scores of the two groups.

b.

95% CI

(X[bar]-X[bar])±t_{n_1+n_2-2;1-\alpha /2}*Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} }

t_{n_1+n_2-2;1-\alpha /2}= t_{18;1.975}= 2.101

(86.8-79.5)±2.101*(9.93\sqrt{\frac{1}{10} +\frac{1}{10} })

[-2.03; 16.63]

With a 95% confidence level, you'd expect that the interval [-2.03; 16.63] would contain the difference between the mean scores of the two classes.

c.

Considering that the null hypothesis wasn't rejected and that at the same level the confidence interval includes the zero, we can affirm that the format of the teaching materials, digital or regular textbooks, has no significant effect on the scores of the students.

I hope it helps!

3 0
4 years ago
PLZ HELP ASAP ASAP ASAP
lara31 [8.8K]

Answer:

what is the question

Step-by-step explanation:

8 0
3 years ago
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How do you find a complementary and supplementary angles
dexar [7]
Complementary angles add up to 90
Supplementary angles add up to 180

12 - Complement - 78
12 - Supplement - 168

45 - Complement - 45
45 - Supplement - 135

83 - Complement - 7
83 - Supplement - 97

63 - Complement - 27
63 - Supplement - 117

4 - Complement - 86
4 - Supplement - 176
7 0
3 years ago
Helen had $12 but spent $3 of it. What per cent did she spend?
Scrat [10]

Answer:

25%

Step-by-step explanation:

3/12 = 0.25 = 25%

6 0
2 years ago
Read 2 more answers
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