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kaheart [24]
4 years ago
8

Given the factors, name the roots. 3. f(x) = -3(2x – 5)(x + 2)

Mathematics
1 answer:
tekilochka [14]4 years ago
6 0

Answer:

x = 5/2

or

x = -2

Step-by-step explanation:

recall that the roots of a function f(x) are basically the values of x that will make f(x) = 0,

we find these values of x by making f(x) = 0 and then solving the equation for x,

in our case,

f(x) = -3(2x – 5)(x + 2)

to find roots,

f(x) = 0

-3(2x – 5)(x + 2) = 0

Equating each factor = 0, the equation can be broken down into:

-3 = 0 (obviously not valid, hence we can ignore this)

or

(2x – 5) = 0     add 5 to both sides

2x = 5              divide both sides by 2

x = 5/2   ( Answer)

or

(x + 2) = 0      subtract 2 from both sides

x = -2 (Answer)

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A real estate agent has 17 properties that she shows. She feels that there is a 50% chance of selling any one property during a
Likurg_2 [28]

Answer:

0.0011 = 0.11% probability of selling less than 3 properties in one week.

Step-by-step explanation:

For each property, there are only two possible outcomes. Either they are sold, or they are not. The chance of selling any one property is independent of selling another property. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A real estate agent has 17 properties that she shows.

This means that n = 17

She feels that there is a 50% chance of selling any one property during a week.

This means that p = 0.5

Compute the probability of selling less than 3 properties in one week.

This is

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{17,0}.(0.5)^{0}.(0.5)^{17} \approx 0

P(X = 1) = C_{17,1}.(0.5)^{1}.(0.5)^{16} = 0.0001

P(X = 2) = C_{17,2}.(0.5)^{2}.(0.5)^{15} = 0.0010

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0 + 0.0001 + 0.0010 = 0.0011

0.0011 = 0.11% probability of selling less than 3 properties in one week.

5 0
3 years ago
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