Answer:
E) 3.53 m/s
Explanation:
KE₁ + RE₁ = KE₂ + RE₂ + PE
½ mv₁² + ½ Iω₁² = ½ mv₂² + ½ Iω₂² + mgh
For a sphere, I = ⅖ mr²
½ mv₁² + ½ (⅖ mr²) ω₁² = ½ mv₂² + ½ (⅖ mr²) ω₂² + mgh
½ mv₁² + ⅕ mr² ω₁² = ½ mv₂² + ⅕ mr² ω₂² + mgh
Rolling without slipping means v = ωr.
½ mv₁² + ⅕ mv₁² = ½ mv₂² + ⅕ mv₂² + mgh
⁷/₁₀ mv₁² = ⁷/₁₀ mv₂² + mgh
⁷/₁₀ v₁² = ⁷/₁₀ v₂² + gh
Substitute:
⁷/₁₀ (5.50 m/s)² = ⁷/₁₀ v₂² + (9.8 m/s²) (3.00 m sin 25.0°)
v₂ = 3.53 m/s
The weight of the automobile is 17,533.6 N.
<h3>
Weight of the automobile</h3>
The weight of the automobile is calculated as follows;
P = F / A
F = (W/4)
P = (W/4) / A
P = W/4A
W = 4AP
where;
W = (4)(217 x 10⁻⁴ m²)(2.02 x 10⁵ Pa)
W = 17,533.6 N
Thus, the weight of the automobile is 17,533.6 N.
Learn more about weight here: brainly.com/question/2337612
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C) Y is the strongest point in the electric field.