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ra1l [238]
3 years ago
10

Explain the error in the solution below. What

Mathematics
1 answer:
ikadub [295]3 years ago
5 0
X5jhahaj661516 ıyqyququuquwuwuıwı
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Please answer fast, I need great answers!!!!! This is mathematics.
Fantom [35]
20, 25, 30, 30, 31, 40, 41, 49
median = 30.5

lower IQR = 27.5
upper IQR = 40.5

Range IQR = 40.5 - 27.5 = 13

answer is 13
7 0
3 years ago
Charles bought 24 blow-pops for $7.20. His little sister Tracy wants 11 blow-pops. How much will 11 blow-pops cost?
Norma-Jean [14]

$3.30 because taking the cost of 24, which is $7.20, and dividing is by the amount, 24, you get that one Blow-Pop costs $0.30. Then to find how many 11 costs you just need to multiply $0.30 by 11, and you get $3.30.

8 0
3 years ago
Find the equation of the tangent at ( 0 , 2) to the circle with equation
erica [24]

Answer:

if this is high school i cant do it

5 0
2 years ago
Kelly runs a bakery that sells Chocolate Blizzards and Mint Breezes. The bakery must make at least 25 dozen and at most 45 dozen
drek231 [11]
Yeah Thanks I love to see that and the answer A
3 0
3 years ago
To obtain information on the corrosion-resistance properties of a certain type of steel conduit, 45 specimens are buried in soil
Debora [2.8K]

Answer:

statistic value t= 5.43

p-value: < 0.00001.

Step-by-step explanation:

Hello!

To obtain information over the corrosion-resistance properties of a certain type of steel conduit a random sample of 45 specimens was taken and buried for two years.

The study variable is:

X: Max. penetration of a steel conduit.

The data of the sample

n= 45

sample mean X[bar]= 53.4

sample standard deviation S= 4.2

The conduits are manufactured to have a true average penetration of at most 50 mills, symbolically: μ ≤ 50

The hypothesis is:

H₀: μ ≤ 50

H₁: μ > 50

α: 0.05

To choose the corresponding statistic to use to study the population mean, the variable must have a normal distribution. There is no available information to check this, so I'll just assume that the variable has a normal distribution and, since the population variance is unknown and the sample is small, the statistic to use is a Student t.

Under the null hypothesis, the critical region and the p-value are one-tailed.

Critical value:

t_{n-1; 1-\alpha } = t_{44; 0.95} = 1.68

Rejection rule:

Reject the null hypothesis when t ≥ 1.68

t= \frac{53.4 - 50}{\frac{4.2}{\sqrt{45} } }

t= 5.43

The calculated value is greater than the critical value, thedecision is to rject the null hypothesis.

p-value:

P(t ≥ 5.43) = 1 - P(t < 5.43) = < 0.00001.

The p-value is less than α so the decision is to reject the null hypothesis.

Since the null hypothesis was rejected, then the population average of the penetration of the conduits specimens is greater than 50 mils. It is not recommendable to use these conduits.

I hope it helps!

4 0
3 years ago
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