Question

The initial population of a town is 2808 grows with a doubling time of 10 years what will the population be in eight years

Answer 1

if the amount doubles, that means the rate of change is 100%, whatever the current amount + 100% of that amount, so it doubles, rate of increase is 100%.

$\bf \textit{Periodic/Cyclical Exponential Growth} \\\\ A=P(1 + r)^{\frac{t}{c}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &2808\\ r=rate\to 100\%\to \frac{100}{100}\dotfill &1.0\\ t=\textit{elapsed time}\dotfill &8\\ c=period\to &10 \end{cases} \\\\\\ A=2808(1 + 1)^{\frac{8}{10}}\implies A=2808(2)^{\frac{4}{5}}\\\\\\ A\approx 2808(1.74)\implies A\approx 4889$