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2 years ago

11

Please give me the correct answer.Only answer if you're very good at math.Take your time when answering.

1 answer:

arlik [135]2 years ago

5 0

Answer:

your answer will be option <u>B) y=20x+30</u>

Step-by-step explanation:

have a great day

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The feet of the average adult woman are 24.6 cm long, and foot lengths are normally distributed. If 16% of adult women have feet

nevsk [136]

Answer:

Approximately 16% of adult women have feet longer than 27.2 cm.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The feet of the average adult woman are 24.6 cm long

This means that $\mu = 24.6$

16% of adult women have feet that are shorter than 22 cm

This means that when $X = 22$ , Z has a p-value of 0.16, so when $X = 22, Z = -1$ . We use this to find $\sigma$

$Z = \frac{X - \mu}{\sigma}$

$-1 = \frac{22 - 24.6}{\sigma}$

$-\sigma = -2.6$

$\sigma = 2.6$

Approximately what percent of adult women have feet longer than 27.2 cm?

The proportion is 1 subtracted by the p-value of Z when X = 27.2. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{27.2 - 24.6}{2.6}$

$Z = 1$

$Z = 1$ has a p-value of 0.84.

1 - 0.84 = 0.16

0.16*100% = 16%.

Approximately 16% of adult women have feet longer than 27.2 cm.

3 0

2 years ago

At a college, 69% of the courses have final exams and 42% of courses require research papers. Suppose that 29% of courses have a

laila [671]

Answer:

a) 0.82

b) 0.18

Step-by-step explanation:

We are given that

P(F)=0.69

P(R)=0.42

P(F and R)=0.29.

a)

P(course has a final exam or a research paper)=P(F or R)=?

P(F or R)=P(F)+P(R)- P(F and R)

P(F or R)=0.69+0.42-0.29

P(F or R)=1.11-0.29

P(F or R)=0.82.

Thus, the the probability that a course has a final exam or a research paper is 0.82.

b)

P( NEITHER of two requirements)=P(F' and R')=?

According to De Morgan's law

P(A' and B')=[P(A or B)]'

P(A' and B')=1-P(A or B)

P(A' and B')=1-0.82

P(A' and B')=0.18

Thus, the probability that a course has NEITHER of these two requirements is 0.18.

3 0

2 years ago

Find the distance between the points given.<br><br> (-3, 2) and (9, -3)<br><br> √(61)<br><br> √(37)

cricket20 [7]

Answer:

d=13.

Step-by-step explanation:

d= $\sqrt{(x_{2}-x_{1} ) ^{2} +(y_{2}-y_{1} ) ^{2}}$

From question statement, $x_{1} =-3$ , $x_{2} =9$

$y_{1} =2$ , $y_{2} =-3$

put above values in the distance formula,we obtain

d= $\sqrt{(9-(-3))^{2}+(-3-2)^{2}}$

d= $\sqrt{(12)^{2}+(-5)^{2}}$

d= $\sqrt{144+25}$

d= $\sqrt{169}$

d=13

8 0

2 years ago

Cooper earned $660 as a furniture salesman this month. His earns a

Grace [21]

Ya got to go $660 + 7% hours later on $450 hours later 00.578 to finish

5 0

3 years ago

On Thursday, 13,450 people attended a baseball game. Only 11,350 people attended the game. Only 11,350 people attended the game

mariarad [96]

First 0-0=0
Next 5-5=0
Then 4-3=1
After 3-1=2
Then 1-1=0
Move comma after 2

3 0

2 years ago