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3 years ago

I need help with 14, 15, and 16 please!!

Mathematics

1 answer:

stellarik [79]3 years ago

7 0

Answer:

so 80 plus 20 is a 100

Step-by-step explanation:

thats it

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Katie practice the flute for 45 minutes then she ate a snack for 15 minutes next she watched television for for 30 minutes until

IrinaK [193]

Well let's see, how about we subtract 6 P.M from 30 minutes and that is 5:30 P.M then we subtract 5:30 by 15 minutes, and we get 5:15 P.M then we subtract 5:15 P.m by 45 minutes and we get 4:30 P.M

4 0

3 years ago

Read 2 more answers

Hi there it's me again! Sorry to bother you, but can someone help me out with this?

stiv31 [10]

Answer:

hey,

your answer Is 1. :)

Step-by-step explanation:

no matter how many lines we try to draw which pass thru broh A and B, there would just be 1 straight line passing thru both points A and B.

I didn't do the activity tho

you can use a plain sheet of paper as a plane. and draw points A and B on it and then connect them drawing a straight line from A to B.

4 0

3 years ago

Answer the following questions about the function whose derivative is f primef′(x)equals=x Superscript negative three fifths Ba

Elden [556K]

Answer:

(a) The critical points of f are x=0 and x=3.

(b)f is decreasing on $(0,3)$ and f is decreasing on $(3,\infty)$ .

(c) Therefore the local minimum of f is at x=3

Step-by-step explanation:

Given function is

$f'(x)= x^{-\frac35}(x-3)$

(a)

To find the critical point set f'(x)=0

$\therefore x^{-\frac35}(x-3)=0$

$\Rightarrow x=0,3$

The critical points of f are 0,3.

(b)

The interval are $(0,3)$ and $(3,\infty)$ .

To find the increasing or decreasing, taking two points one point from the interval (0,3) and another point $(3,\infty)$ .

Assume 1 and 4.

Now $f'(1)=(1)^{-\frac35}(1-3)$

and $f'(4)=(4)^{-\frac35}(4-3)>0$

Since 1∈ $(0,3)$ , f'(x)<0 and 4∈ $(3,\infty)$ , f'(x)>0

∴f is decreasing on $(0,3)$ and f is decreasing on $(3,\infty)$ .

(c)

$f'(x)= x^{-\frac35}(x-3)$

Differentiating with respect to x

$f''(x)=-\frac35x^{-\frac 85}(x-3)+x^{-\frac35}$

Now

$f''(0)=-\frac35(0)^{-\frac 85}(0-3)+(0)^{-\frac35}=0$

and

$f''(3)=-\frac35(3)^{-\frac 85}(3-3)+3^{-\frac35}$

$=0.517>0$

Since f''(x)>0 at x=3

Therefore the local minimum of f is at x=3

8 0

3 years ago

Graph the line with slope - 3/4 passing through point (4,-5)

Arlecino [84]

Answer:

The graph in the attached figure

Step-by-step explanation:

we know that

The equation of the line in point slope form is equal to

$y-y1=m(x-x1)$

we have

$m=-\frac{3}{4}$

$point\ (4,-5)$

substitute

$y+5=-\frac{3}{4}(x-4)$

Convert to slope intercept form

$y=mx+b$

isolate the variable y

$y+5=-\frac{3}{4}x+3$

$y=-\frac{3}{4}x+3-5$

$y=-\frac{3}{4}x-2$

Find the intercepts

Find the y-intercept (value of y when the value of x is equal to zero)

For x=0

$y=-\frac{3}{4}(0)-2=-2$

The y-intercept is (0,-2)

Find the x-intercept (value of x when the value of y is equal to zero)

For y=0

$0=-\frac{3}{4}x-2$

$x=-\frac{8}{3}=-2.667$

The x-intercept is (-2.667,0)

To graph the line plot the intercepts and join the points

see the attached figure

3 0

3 years ago

one number is 1 less than a second number. twice the second number is 6 less than 4 times the first. find the two numbers.

mixas84 [53]

One number is 4 and the second number is 5.

8 0

4 years ago