Answer: (-3,0)
To get this answer, we subtract 5 from the x coordinate and add 2 to the y coordinate. Point A is located at (x,y) = (2,-2) so we see that x = 2 and y = -2
Subtract 5 from the x coordinate: x-5 = 2-5 = -3. The new x coordinate is -3
Add 2 to the y coordinate: y+2 = -2+2 = 0. The new y coordinate is 0.
Therefore, using the rule (x,y) --> (x-5,y+2) has the mapping (2,-2) ---> (-3,0)
Check out the attached image.
H = 2f / (m+1)
[multiply by (m+1)]
h(m+1) = 2f
[divide by 2]
f = (h (m + 1)) / 2
3b / (b+2) = 12 / (b+2)
[multiply by (b+2)]
3b = 12
[divide by 3]
b = 4
3 / (6x + 1) / 2 = 8 / (x + 4) / 3
[multiply both denominators to mike one denominator]
3 / 8(6x+1) = 8 / 3(x+4)
[expand brackets]
3 / (48x + 8) = 8 / (3x + 12)
[multiply by (48x + 8)]
3 = 8(48x + 8) / (3x+12)
[multiply by (3x+12)]
3(3x +12) = 4(48x + 8)
[simplify]
9x + 36 = 192x + 32
173x = 4
x = 4 / 173
Answer:
y
=1
/3
x
+
14
/3
Step-by-step explanation:
Answer:
The answer to the question provided is 
.
.
Step-by-step explanation:
☆Happy to help!
Find the smallest number that is divisible by 2, 3, 4, 5, 6 and add 1.
We need the least common multiple of 2, 3, 4, 5, 6.
2 = 2
3 = 3
4 = 2^2
5 = 5
6 = 2 * 3
LCM = product of common and not common prime factors with larger exponent.
LCM = 2^2 * 3 * 5 = 4 * 3 * 5 = 60
To always have a remainder of 1, you need of add 1 to 60.
The number is 61.
Check:
61/2 = 30 remainder 1
61/3 = 20 remainder 1
61/4 = 15 remainder 1
61/5 = 12 remainder 1
61/6 = 10 remainder 1
