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LekaFEV [45]
3 years ago
10

Consider this query:

Computers and Technology
1 answer:
vlabodo [156]3 years ago
4 0

Answer:

There is a table in the database named Teacher having columns Email, Expiry Month etc. this query is selecting the email address from the table Teachers on the basis of expiry month that is February.\  

Explanation:

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8.17 Lab: Strings of a Frequency Write a program that reads whitespace delimited strings (words) and an integer (freq). Then, th
gavmur [86]

Answer:

def occurencesOfWords(words,freq):

  frequency_dictionary={}

  matched_frequency_words=[]

  for i in range(len(words)):

      counter=1

      a=words[i].lower()

      for j in range(len(words)):

          if(i==j):

              continue

          b=words[j].lower()

          if(a==b):

              counter+=1

      frequency_dictionary[words[i]]=counter

  for key in frequency_dictionary:

      if(frequency_dictionary[key]==freq):

          matched_frequency_words.append(key)

  return matched_frequency_words

if __name__=='__main__':

  user_input=input()

  freq=int(input())

  words=user_input.split(" ");

  required_words=occurencesOfWords(words,freq)

  for s in required_words:

      print(s)

Explanation:

  • Inside the occurencesOfWords function, initialize a frequency_dictionary that is used to store the string and the frequency of that specific string .
  • matched_frequency_words is an array that is used to store each string whose frequency matches with the provided frequency
  • Run a nested for loop up to the length of words and inside the nested for loop, skip the iteration if both variables i and j are equal as both strings are at same index.
  • Increment the counter variable, if two string are equal.
  • Loop through the frequency_dictionary to get the matching frequency strings .
  • Finally test the program inside the main function.
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Complete the sentence.
KatRina [158]

Answer:

tCP

Explanation:

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